Question

注册服务商希望解析包含许多学生数据的文本文件。

输入文件：许多学生数据的文本文件（每个学生文件的格式相同）

我成功地找到了一个“模式”并将其打印到文件中，这是我需要的75％。在一种情况下，找到匹配项并打印了匹配行后，我需要打印下一行。那就是我迷路的地方。 [可迭代，迭代器，生成器...对我来说都是希腊语]

文字示例：

Student............: StudentA
Program............: BA Adol Biology Education (ED.ADOL.BIO.BA)

C) 3: Lab Science Course
Complete 1 Lab Science course
CHM-111 General Chemistry I *4..... FA2018   A         4

I) 4: Adolescent Biology Education Major
Credits: 24
GPA Achieved/Needed: 4.000 / 2.500
Complete all 3 subrequirements:
I) A: Educ Requirements
COMPLETE 2 GROUPS
Credits: 5
GPA Achieved/Needed: none / 3.000
I) Group 1
Student............: StudentB
Program............: BA Adol Eng Education (ED.ADOL.ENG.BA)

C) 3: Lab Science Course
Complete 1 Lab Science course;
CHM-111 General Chemistry I *4..... FA2018   A         4
I) 4: Adolescent English Education Major
Credits: 24
GPA Achieved/Needed: 4.000 / 2.500
Complete all 3 subrequirements:
I) A: Educ Requirements
COMPLETE 2 GROUPS
Credits: 5
GPA Achieved/Needed: none / 3.000
I) Group 1
Student............: StudentC
Program............: BA Adol Chemistry Education (ED.ADOL.CHM.BA)

C) 3: Lab Science Course  
Complete 1 Lab Science course;
CHM-111 General Chemistry I *4..... FA2018   A         4
I) 4: Adolescent Chemistry Education Major
Credits: 24
GPA Achieved/Needed: 4.000 / 2.500
Complete all 3 subrequirements:
I) A: Educ Requirements
COMPLETE 2 GROUPS
Credits: 5

运行Python 3.7.1；尝试过与__next__()一起玩，但是没有成功。从我读过的print()来看，将指针移到了下一行...所以我尝试这样做，但这不起作用。

outfile = open('result.txt', 'w')
with open('BEVL_EDU.txt','r') as inFile:
f = inFile.read().splitlines()
for line in f:
    if 'Student...' in line:
        outfile.write(line + '\n')
    if '4:' in line:
        outfile.write(line + '\n')
        print(line)                 # --> this is where I tried to move the pointer to next line
        outfile.write(line + '\n')  # --> and then print the "next" line :-)
    if 'GPA Achieved/Needed' in line:
        outfile.write(line + '\n')

Answer 1

首先应该做一些事情，以使您的代码更符合地道的python。可以直接迭代文件。所以代替：

f = inFile.read().splitlines()

您应该使用：

for line in inFile:

现在，我们已经像在python中一样直接在您的文件上运行代码，您只需调用next(inFile)就可以在文件中获得下一行。这将推进文件迭代器并返回值，并且不会中断您的for循环。

如何匹配单词，在文件中一遍又一遍地打印行和下一行

1 个答案: