我的组件
class Admin extends React.Component {
constructor(props) {
super(props);
}
uploadFile = async (event, refetch) => {
await uploadFileToBucket(event, true);
refetch(); // refetch is undefined
};
render() {
return (
<GraphQlDataFetcher query={getObjectsInDefaultBucket()}>
{(data, refetch) => (
<Files files={data.bucketObjects}/>
<input type="file" onChange={(refetch) => this.uploadFile(event, refetch)}/>
)}
</GraphQlDataFetcher>
);
}
}
export default Admin
文件上传完成后,我想重新获取graphql查询。因此,我需要将refetch函数发送到我的uploadFile
。我该怎么办?
答案 0 :(得分:2)
我认为这样做:
<input type="file" onChange={ (refetch) => this.uploadFile(event, refetch) } />
您要覆盖refetch
传递的GraphQlDataFetcher
方法,您可以尝试这样做吗?
<input type="file" onChange={ event => this.uploadFile(event, refetch) } />
答案 1 :(得分:1)
0xc14m1z的答案正确。
这是一种“更清洁”的语法,可通过预先配置功能来解决您的问题:
<input type="file" onChange={this.uploadFile(refetch)} />
还有您的功能:
uploadFile = async refetch => event => {