Question

我有一个从console.log（temp）显示的数组，如下所示：

temp = [{name: "Request A", data: "1"}
       {name: "Request B", data: "12"}
       {name: "Request C", data: "6"}]

如果我想更改数组格式应该怎么做？

 temp: [{name: "Request A", data: [1]}
       {name: "Request B", data: [12]}
       {name: "Request C", data: [6]}]

请帮助大家...谢谢

Answer 1

使用'IsUserText函数将返回一个新数组，并使用map将字符串转换为数字

parseInt

Answer 2

要更改数组，您可以遍历<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <select id="fruit"> <option>Apple</option> <option>Pear</option> </select>的项目，只需更改属性即可：

forEach

Answer 3

您可以使用map

let temp =  [{name: "Request A", data: "1"},{name: "Request B", data: "12"},{name: "Request C", data: "6"}]

let op = temp.map(e=> {
  return {
    ...e,
    data : [+e.data]
  }
})

console.log(op)

Answer 4

尝试一下

temp = [{name: "Request A", data: "1"},
       {name: "Request B", data: "12"},
       {name: "Request C", data: "6"}];


  let temp1 = temp.map(item => {
    item.data = [parseInt(item.data)]
    return item;
  })

  console.log(temp1);

输出：

[ { "name": "Request A", "data": [ 1 ] }, { "name": "Request B", "data": [ 12 ] }, { "name": "Request C", "data": [ 6 ] } ]

Answer 5

尝试

temp.forEach(x=> x.data=[+x.data]);

let temp = [{name: "Request A", data: "1"},
       {name: "Request B", data: "12"},
       {name: "Request C", data: "6"}];
       
       
temp.forEach(x=> x.data=[+x.data]);

console.log(JSON.stringify(temp));

Answer 6

尝试一下- 我正在使用Array.of创建一个数组。 +运算符可将字符串解析为Array。

temp.map(t => (t.data = Array.of(+t.data), t));

Answer 7

这是一种方法。这是来自节点REPL。

> var temp = [{name: "Request A", data: "1"}, {name: "Request B", data: "12"}, {name: "Request C", data: "6"}];
undefined
> temp.forEach(function(e) {
..... e.data = [parseInt(e.data, 10)];
..... });
undefined
> temp
[ { name: 'Request A', data: [ 1 ] },
  { name: 'Request B', data: [ 12 ] },
  { name: 'Request C', data: [ 6 ] } ]
>

在JavaScript中将字符串转换为数组内部的整数

7 个答案: