我尝试从rest api获取一个用户,以便在我的android应用中登录以获取此信息,我有下一个代码
LoginActivity.java
public class LoginActivity extends AppCompatActivity {
private LoginViewModel loginViewModel;
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
ActivityLoginBinding binding = DataBindingUtil.setContentView(this, R.layout.activity_login);
loginViewModel = ViewModelProviders.of(this).get(LoginViewModel.class);
binding.setLoginViewModel(loginViewModel);
binding.setLifecycleOwner(this);
loginViewModel.user.observe(this, new Observer<User>() {
@Override
public void onChanged(@Nullable User user) {
Toast.makeText(getApplicationContext(), user.toString(), Toast.LENGTH_LONG).show();
}
});
}
}
LoginViewModel.java
public class LoginViewModel extends ViewModel {
private LoginRespository loginRespository = new LoginRespository();
public MutableLiveData<User> user = new MutableLiveData<>();
public MutableLiveData<String> email = new MutableLiveData<>();
public MutableLiveData<String> password = new MutableLiveData<>();
public LoginViewModel() {}
public void onLoginClicked() {
user = loginRespository.doLogin(email.getValue(), password.getValue());
}
}
LoginRepository.java
@Singleton
public class LoginRespository {
private APIInterface apiInterface;
public LoginRespository(){
this.apiInterface = APIClient.getClient().create(APIInterface.class);
}
//private final APIInterface apiInterface;
/*@Inject
public LoginRespository(APIInterface apiInterface) {
this.apiInterface = apiInterface;
}*/
public MutableLiveData<User> doLogin(String email, String password) {
final MutableLiveData<User> data = new MutableLiveData<>();
Call<User> call = apiInterface.doGetLogin(email, password, APIClient.X_API_KEY, APIClient.X_CLIENT_ID);
call.enqueue(new Callback<User>() {
@Override
public void onResponse(Call<User> call, Response<User> response) {
User user = response.body();
Log.d("#####0", user.toString());
if (user.code.equals(APIClient.Codes.OK)){
Log.d("#####1", user.toString());
data.setValue(user);
Log.d("#####2", data.toString());
}
}
@Override
public void onFailure(Call<User> call, Throwable t) {
call.cancel();
}
});
return data;
}
}
User.java
public class User{
@SerializedName("code")
@Expose
public String code;
@SerializedName("data")
@Expose
public List<Datum> data = null;
@SerializedName("description")
@Expose
public String description;
@SerializedName("datetime")
@Expose
public String datetime;
/**
* No args constructor for use in serialization
*
*/
public User() {
}
/**
*
* @param description
* @param data
* @param code
* @param datetime
*/
public User(String code, List<Datum> data, String description, String datetime) {
super();
this.code = code;
this.data = data;
this.description = description;
this.datetime = datetime;
}
@Override
public String toString() {
return "User{" +
"code='" + code + '\'' +
", data=" + data +
", description='" + description + '\'' +
", datetime='" + datetime + '\'' +
'}';
}
}
在视图中,我有两个EditText可以登录并可以正常工作,因为我可以将电子邮件和密码传递到LoginRepositori.doLogin中,并且得到用户的响应,但是当我想获取有关用户数据的更新时,使用loginViweMode.User.observe进行活动...我从没收到通知。
然后怎么做,为此将调用活动中的loginViewModel.User.observe...。
谢谢。
答案 0 :(得分:1)
您要在下面的调用中创建一个新的user
LiveData
实例(与您在LoginActivity
中实际观察到的实例不同。
public void onLoginClicked() {
user = loginRespository.doLogin(email.getValue(), password.getValue());
}
答案 1 :(得分:1)
您错过了活动和视图模型之间的某些联系。由于每次user
都将无法观察到存储库返回新的实时数据对象,因为其值已由登录调用替换。
要解决此问题,您可以将用户实时数据传递到存储库并从存储库更新其值,而不是在每次调用中创建新对象
或者您可以使用switchMap()转换函数将结果转换为user
变量