MySQL结合两个具有相同结构的查询并添加列

Question

1。我有一个查询来获取每个日期上每个worksite出现多少用户的总和。

2。我还有一个查询，查询每个日期在工作现场制作了多少文件

由于两个表的格式相同，是否可以将每个工作地点和日期的＃1值和每个工作地点和日期的＃2值合并起来，以便它们出现在同一表的另一列上？

看起来像这样：

| Worksite   | Date       | Users On Site | Completed |
| ---------- | ---------- | -----------   | --------- |
| worksite_1 | 2019-01-01 | 2             | 2
| worksite_2 | 2019-01-01 | 0             | 2
| worksite_1 | 2019-01-02 | 1             | 1
| worksite_2 | 2019-01-02 | 0             | 2 
| worksite_1 | 2019-01-03 | 2             | 2            
| worksite_1 | 2019-01-04 | 1             | 1             
| worksite_2 | 2019-01-04 | 0             | 1            
| worksite_1 | 2019-01-05 | 1             | 1             
| worksite_2 | 2019-01-05 | 0             | 1            
| worksite_1 | 2019-01-06 | 1             | 1            
| worksite_2 | 2019-01-06 | 0             | 1

---

＃1

模式（MySQL v5.7）

CREATE TABLE OnSite
    (`uid` varchar(55), `worksite_id`  varchar(55), `timestamp` datetime)
;

INSERT INTO OnSite
    (`uid`, `worksite_id`, `timestamp`)
VALUES
  ("u12345", "worksite_1", '2019-01-01'),
  ("u12345", "worksite_1", '2019-01-02'),
  ("u12345", "worksite_1", '2019-01-03'),
  ("u12345", "worksite_1", '2019-01-04'),
  ("u12345", "worksite_1", '2019-01-05'),
  ("u12345", "worksite_1", '2019-01-06'),
  ("u1", "worksite_1", '2019-01-01'),
  ("u1", "worksite_1", '2019-01-02'),
  ("u1", "worksite_1", '2019-01-05'),
  ("u1", "worksite_1", '2019-01-06')

;

---

查询＃1

SELECT    worksite_id, DATE(timestamp) Date, COUNT(DISTINCT uid) `Users On Site`
FROM      OnSite
GROUP BY  DATE(timestamp), worksite_id;

| worksite_id | Date       | Users On Site |
| ----------- | ---------- | ------------- |
| worksite_1  | 2019-01-01 | 2             |
| worksite_1  | 2019-01-02 | 2             |
| worksite_1  | 2019-01-03 | 1             |
| worksite_1  | 2019-01-04 | 1             |
| worksite_1  | 2019-01-05 | 2             |
| worksite_1  | 2019-01-06 | 2             |

---

View on DB Fiddle

---

＃2

模式（MySQL v5.7）

CREATE TABLE Documents
    (`document_id` varchar(55), `uid` varchar(55), `worksite_id`  varchar(55), `type` varchar(55), `timestamp` datetime)
;

INSERT INTO Documents
    (`document_id`, `uid`, `worksite_id`, `type`, `timestamp`)

VALUES
  ("1",     "u12345",   "worksite_1", 'work_permit',    '2019-01-01 00:00:00'),
  ("2",     "u12345",   "worksite_2", 'job',            '2019-01-01 00:00:00'),
  ("3",     "u12345",   "worksite_1", 'work_permit',    '2019-01-02 00:00:00'),
  ("4",     "u12345",   "worksite_2", 'job',            '2019-01-02 00:00:00'),
  ("5",     "u12345",   "worksite_1", 'work_permit',    '2019-01-03 00:00:00'),
  ("6",     "u12345",   "worksite_2", 'job',            '2019-01-04 00:00:00'),
  ("7",     "u12345",   "worksite_1", 'work_permit',    '2019-01-04 00:00:00'),
  ("8",     "u12345",   "worksite_2", 'work_permit',    '2019-01-05 00:00:00'),
  ("9",     "u12345",   "worksite_1", 'job',            '2019-01-05 00:00:00'),
  ("10",    "u12345",   "worksite_2", 'work_permit',    '2019-01-06 00:00:00'),
  ("11",    "u12345",   "worksite_1", 'work_permit',    '2019-01-06 00:00:00'),
  ("12",    "u12345",   "worksite_2", 'work_permit',    '2019-01-01 00:00:00'),
  ("13",    "u12345",   "worksite_1", 'job',            '2019-01-01 00:00:00'),
  ("14",    "u12345",   "worksite_2", 'work_permit',    '2019-01-02 00:00:00'),
  ("15",    "u12345",   "worksite_1", 'work_permit',    '2019-01-03 00:00:00')

;

---

查询＃2

SELECT    worksite_id 'Worksite', 
          Date(timestamp) Date,
          COUNT(worksite_id) `Completed`
FROM      Documents
GROUP BY  Date(timestamp), worksite_id;

| Worksite   | Date       | Completed |
| ---------- | ---------- | --------- |
| worksite_1 | 2019-01-01 | 2         |
| worksite_2 | 2019-01-01 | 2         |
| worksite_1 | 2019-01-02 | 1         |
| worksite_2 | 2019-01-02 | 2         |
| worksite_1 | 2019-01-03 | 2         |
| worksite_1 | 2019-01-04 | 1         |
| worksite_2 | 2019-01-04 | 1         |
| worksite_1 | 2019-01-05 | 1         |
| worksite_2 | 2019-01-05 | 1         |
| worksite_1 | 2019-01-06 | 1         |
| worksite_2 | 2019-01-06 | 1         |

---

View on DB Fiddle

Answer 1

您可以使用JOIN。例如：

SELECT
  IFNULL(OnSite.worksite_id, Documents.worksite_id) as `Worksite`,
  DATE(IFNULL(OnSite.timestamp, Documents.timestamp)) as `Date`,
  COUNT(DISTINCT OnSite.uid) as `Users_On_Site`,
  COUNT(Documents.worksite_id) as `Completed`
FROM OnSite
  LEFT JOIN Documents ON OnSite.worksite_id = Documents.worksite_id AND DATE(OnSite.timestamp) = DATE(Documents.timestamp)
GROUP BY `Date`, `Worksite`;