如何为域和子域创建合适的数据库结构?

时间:2019-01-16 20:29:20

标签: python sql orm sqlalchemy

我有一个域列表和一个子域列表。例如:

域A具有子域a1,a2,a3。
域B具有子域b1,b2,b3。
域C没有子域

我需要创建数据库结构,以便可以这样进行排序:

A
a1
a2
a3
B
b1
C

我需要清楚地看到哪个是哪个域的域或子域。

我试图使用ForeignKey到域将域放在一个表中,将子域放在另一表中。

class Domain(Base):
    __tablename__ = "domains"
    domain_id = Column(Integer(), primary_key=True)
    name = Column(String(), unique=True)


class Subdomain(Base):
    __tablename__ = "subdomains"
    subdomain_id = Column(Integer(), primary_key=True)
    name = Column(String(), unique=True)
    domain_id = Column(Integer, ForeignKey('domains.domain_id'))

我正在使用此表中的域和子域来创建第三张表:

class Title(Base):
    __tablename__ = "titles"
    title_id = Column(Integer(), primary_key=True)
    domain_id = Column(Integer, ForeignKey('domains.domain_id'))
    subdomain_id = Column(Integer, ForeignKey('subdomains.subdomain_id')) -- NULL if that is a Domain
    title = Column(String())
    status = Column(Integer())

1 个答案:

答案 0 :(得分:0)

您要的是数据模型和SQL查询。

您可以使用两个表:

  • 域(domain_id,名称)
  • 子域(subdomain_id,名称,domain_id)

使用此查询:

select name
from
(
  select name, name as domain_name, 'domain' as type
  from domain
  union all
  select sd.name, d.name as domain_name, 'subdomain' as type
  from domain d
  join subdomain sd on sd.domain_id = d.domain_id
)
order by domain_name, type, name;

或者只有一张桌子:

  • 域(domain_id,名称,parent_domain_id)

使用此查询:

select name
from
(
  select name, name as domain_name, 'domain' as type
  from domain
  where parent_domain_id is null
  union all
  select sd.name, d.name as domain_name, 'subdomain' as type
  from domain d
  join domain sd on sd.parent_domain_id = d.domain_id
)
order by domain_name, type, name;
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