每天只获取SQL中的多个条目的最后一行

时间:2011-03-24 19:30:19

标签: sql-server tsql sql-server-2008

我有一张桌子,例如:

Id        Name        EnteredOn                    Percentage
`````````````````````````````````````````````````````````````
01        person1     2011-03-09 17:29:35.683      56.29
02        person1     2011-03-09 17:29:35.731      76.29
03        person1     2011-03-09 18:15:78.683      56.29
04        person1     2011-03-10 17:29:35.683      56.29
05        person1     2011-03-10 16:29:31.683      56.29
06        person1     2011-03-11 17:29:35.683      56.29

总结上表,白天 09 三个行, 10 两个行>

现在,我只想选择最新一行 - 一行 - 每天  (一行为9,一行为10,另一行为11)

由于时间戳,我不能使用distinct。我不能分组并使用:

CAST(CONVERT(FLOAT, EnteredOn) AS INT)

因为当我选择EnteredOn字段时,它会抱怨它没有分组。我无法合并distinct(cast..date...),因为我无法获得正确的语法。

如何选择 - 仅名称,已输入,百分比字段与每天不同?

提前多多感谢。

4 个答案:

答案 0 :(得分:14)

;with cte as
(
  select
    *,
    row_number() over(partition by datediff(d, 0, EnteredOn) order by EnteredOn desc) as rn 
  from YourTable
)
select *
from cte  
where rn = 1

答案 1 :(得分:8)

1行/天:

SELECT t1.Name, t1.EnteredOn, t1.Percentage
  FROM table t1
  JOIN (SELECT MAX(EnteredOn) Max_EnteredOn_By_Day
          FROM table 
         GROUP BY convert(varchar, EnteredOn, 112)) t2
  ON t1.EnteredOn = t2.Max_EnteredOn_By_Day

1行/人/天:

SELECT t1.Name, t1.EnteredOn, t1.Percentage
  FROM table t1
  JOIN (SELECT Name, MAX(EnteredOn) Max_EnteredOn_By_Day
          FROM table 
         GROUP BY Name, convert(varchar, EnteredOn, 112)) t2
  ON t1.Name = t2.Name
 AND t1.EnteredOn = t2.Max_EnteredOn_By_Day

答案 2 :(得分:6)

SELECT Name, EnteredOn, Percentage
FROM (  SELECT *, ROW_NUMBER() OVER(PARTITION BY CONVERT(VARCHAR(8),EnteredOn,112) ORDER BY EnteredOn DESC) Corr
        FROM YourTable) A
WHERE Corr = 1

答案 3 :(得分:2)

我建议在这里再说一遍:

select top 1 with ties 
    Name, EnteredOn, Percentage
from YourTable
order by row_number() over(partition by datediff(d, 0, EnteredOn) order by Name, EnteredOn desc)
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