Question

我刚刚开始学习Swift，并在操场上制作了Roulette类的应用程序。

我在不同的情况和条件下使用了switch和case控制流。我花了 156行来完成轮盘赌的全部36种可能性，当然还有红色和黑色。

有没有办法做到这一点？我做错了吗？

let number = Int.random(in: 0 ..< 37)
let color = Int.random(in: 1 ..< 3)

let NumberColor = (number, color)
let Red = "and the color is Red"
let Black = "and the color is Black"

switch NumberColor {
case (0, _):
print("The number is 0 and the color is Green!")
case  (1, 1):
print("The Number is 1 \(Red)")
case  (1, 2):
print("The Number is 1 \(Black)")
case  (2, 1):
print("The Number is 2 \(Red)")
case  (2, 2):
print("The Number is 2 \(Black)")
case  (3, 1):
print("The Number is 3 \(Red)")
case  (3, 2):
print("The Number is 3 \(Black)")
case  (4, 1):
print("The Number is 4 \(Red)")
case  (4, 2):
print("The Number is 4 \(Black)")
case  (5, 1):
print("The Number is 5 \(Red)")
case  (5, 2):
print("The Number is 5 \(Black)")
case  (6, 1):
print("The Number is 6 \(Red)")
case  (6, 2):
print("The Number is 6 \(Black)")
case  (7, 1):
print("The Number is 7 \(Red)")
case  (7, 2):
print("The Number is 7 \(Black)")
case  (8, 1):
print("The Number is 8 \(Red)")
case  (8, 2):
print("The Number is 8 \(Black)")
case  (9, 1):
print("The Number is 9 \(Red)")
case  (9, 2):
print("The Number is 9 \(Black)")
case  (10, 1):
print("The Number is 10 \(Red)")
case  (10, 2):

依次类推，直到代码分别到达大小写（36，1）和大小写（36，2）

结果还可以！我需要知道是否有更短的代码编写方法，可以用循环或我不知道的东西减少行数。

Answer 1

您的整个代码可以很简单：

let number = Int.random(in: 0 ..< 37)
let color = Int.random(in: 1 ..< 3)

print("The Number is \(number) and the color is \(color == 1 ? "Red" : "Black")")

就是这样。不需要元组或switch。

Answer 2

您可以将代码简化为：

let number = Int.random(in: 0 ... 36)
let color = Int.random(in: 1 ... 2)

switch (number, color) {
case (0, _):
    print("The number is 0 and the color is Green!")

case (_, 1):
    print("The number is \(number) and is Red")

case (_, 2):
    print("The number is \(number) and is Black")

default:
    break
}

现在，很明显，在实际的轮盘赌轮上，颜色和数字并不是像此代码所建议的那样独立，但这是一种简化代码同时又使意图清晰的方法。

有没有办法减少Swift代码行的数量？

2 个答案: