Question

我目前有一个看起来像这样的数组：

var array = [
      {
        "name": "a",
        "age": 1,
        "siblings": 3
      },
      {
        "name": "b",
        "age": 3,
        "siblings": 5
      },
      {
        "name": "a",
        "age": 1,
        "siblings": 2
      }
]

我想创建一个具有2个值的函数，并返回一个包含与这两个值匹配的对象的新数组。

var name = "a";
var age = 1;
someFunction(name, age);

并返回如下所示的内容：

newArray = [
      {
        "name": "a",
        "age": 1,
        "siblings": 3
      },
      {
        "name": "a",
        "age": 1,
        "siblings": 2
      }

]

我尝试使用filter方法和reduce方法，但没有成功。如果有人可以帮助我或指出正确的方向，我将不胜感激。

var array = [
      {
        "name": "a",
        "age": 1,
        "siblings": 3
      },
      {
        "name": "b",
        "age": 3,
        "siblings": 5
      },
      {
        "name": "a",
        "age": 1,
        "siblings": 2
      }
]

 var result = array.filter(function(obj) {
           return obj.name === "a" && obj.age === 1;
           });
    return result[0];
 }
console.log(result);

Answer 1

您可以将包含所需键/值对的数组用于搜索。

以Array#filter的谓词作为对Array#every的检查。

var array = [{ name: "a", age: 1, siblings: 3 }, { name: "b", age: 3, siblings: 5 }, { name: "a", age: 1, siblings: 2 }],
    search = [['name', 'a'], ['age', 1]],
    result = array.filter(object => search.every(([key, value]) => object[key] === value));

console.log(result);

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Answer 2

这是您的工作功能

function someFunction (name, age) {
    return array.filter(val => val.name == name && val.age == age)
}

Answer 3

在Array#filter回调中，只需将当前元素的name和age与您传递的参数进行比较。

var array = [{"name":"a","age":1,"siblings":3},{"name":"b","age":3,"siblings":5},{"name":"a","age":1,"siblings":2}]
var name = "a";
var age = 1;
function someFunction(name, age){
 return array.filter((obj) => obj.name === name && obj.age === age)
}
console.log(someFunction(name, age));

您也可以使用Array#reduce。只需将匹配的对象添加到累加器数组中并返回即可。

var array = [{"name":"a","age":1,"siblings":3},{"name":"b","age":3,"siblings":5},{"name":"a","age":1,"siblings":2}]
var name = "a";
var age = 1;
function someFunction(name, age){
 return array.reduce((acc, obj) => {
   if(obj.name === name && obj.age === age) 
     acc.push(obj);
   return acc;
 }, []);
}
console.log(someFunction(name, age));

Answer 4

使用过滤器功能

var array = [
  {
    "name": "a",
    "age": 1,
    "siblings": 3
  },
  {
    "name": "b",
    "age": 3,
    "siblings": 5
  },
  {
    "name": "a",
    "age": 1,
    "siblings": 2
  }
]
var name = "a";
var age = 1;
someFunction(name, age);
function someFunction(name,age)
{
console.log(array.filter((e)=>e.name==name && e.age==age?true:false
))}

Answer 5

尝试

let array = [
  {
    "name": "a",
    "age": 1,
    "siblings": 3
  },
  {
    "name": "b",
    "age": 3,
    "siblings": 5
  },
  {
    "name": "a",
    "age": 1,
    "siblings": 2
  }
];

function someFunction(name, age) {
  let newArray = [];
  array.forEach(function(arr) {
    let nameMatch = false;
    let ageMatch = false;
    let obj = arr;
    for(key in obj) {
      if(obj.hasOwnProperty(key)) {
        if(key === 'name') {
          // console.log('name key i am', key);
          let nameValue = obj[key];
          if(nameValue === name) {
            nameMatch = true;
            // console.log('name match', nameValue, name);
          }
        } else if(key === 'age') {
          let ageValue = obj[key];
          if(ageValue === age) {
             // console.log('age match', ageValue, age);
             ageMatch = true
          }
        }
      } 
    }
    if(ageMatch &&  nameMatch) {
      // console.log('true');
      newArray.push(arr);
      // console.log(arr);
    }
  });

  return newArray;
}

let name = "a";
let age = 1;
let myArr = someFunction(name, age);
console.log('My Arr', myArr);

遍历对象数组，以查找包含2个值的对象

5 个答案: