根据大小用颜色填充Python海龟中的多边形

时间:2019-01-26 22:46:37

标签: python turtle-graphics

由Turtle绘制的Random(?)生成的多边形需要根据其大小填充颜色,但不会填充完成的形状。 这是我已经编写的代码。

import turtle, random

def drawpoly (sTurtle, sSides, sLength):
    for i in range (sSides):
        sTurtle.begin_fill()
        sTurtle.forward(sLength)
        sTurtle.left(360/sSides)
        sTurtle.end_fill()

sides = random.randint (3, 21)
size = random.randint (30, 200)

wn = turtle.Screen()
wn.bgcolor('black')

mac = turtle.Turtle()
mac.color('black')
mac.fillcolor()
mac.pensize(3)

for each in (size, sides):
    if each <= 99:
        mac.fillcolor('red')
    elif each <= 149:
        mac.fillcolor('white')
    elif each >149:
        mac.fillcolor('blue')

drawpoly(mac, sides, size)

最后,我尝试的大多数操作最终仅更改了Turtle线条颜色。我似乎无法获得Mac(乌龟)绘制的(半随机)多边形以填充颜色。

1 个答案:

答案 0 :(得分:0)

我发现的主要问题是以下代码:

for i in range (sSides):
    sTurtle.begin_fill()
    sTurtle.forward(sLength)
    sTurtle.left(360/sSides)
    sTurtle.end_fill()

您正在尝试填充线条而不是多边形。您真正想要的是:

sTurtle.begin_fill()
for i in range (sSides):
    sTurtle.forward(sLength)
    sTurtle.left(360/sSides)
sTurtle.end_fill()

这段代码简直令人困惑:

for each in (size, sides):
    if each <= 99:
        mac.fillcolor('red')
    elif each <= 149:
        mac.fillcolor('white')
    elif each >149:
        mac.fillcolor('blue')

您说您要根据 size 进行着色,但最后要覆盖它,并按 sides 进行着色。这是我对您的代码的重做,可以解决这两个问题:

from turtle import Screen, Turtle
from random import randint

def drawpoly(sTurtle, sSides, sLength):
    sTurtle.begin_fill()
    for _ in range(sSides):
        sTurtle.forward(sLength)
        sTurtle.left(360 / sSides)
    sTurtle.end_fill()

sides = randint(3, 21)
size = randint(30, 200)

wn = Screen()
wn.bgcolor('black')

mac = Turtle()
mac.pensize(3)

if size < 100:
    mac.fillcolor('red')
elif size < 150:
    mac.fillcolor('white')
else:
    mac.fillcolor('blue')

drawpoly(mac, sides, size)

wn.exitonclick()
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