如何显示至少有10个销售的商店

Question

我有一张桌子，上面有商店（编号，商店名称，地址）和另一张表销售（商店编号，产品，价格，数量）。 我如何显示至少有10个销售量的商店，

我知道这行代码不好where count(shopsid) >= 10

select id, shopname from shops
join sales on sales.shopsid = shops.id
where count(shopsid) >= 10
order by id;

我要看的是至少有10个销售的商店的ID。 而且我不知道如何使这项工作有效或正确实施。

Answer 1

select id, shopname from shops
join sales on sales.shopsid = shops.id
GROUP BY id, shopname
HAVING count(shopsid) >= 10
order by id;

Answer 2

使用聚合函数时必须使用分组依据

    Select Id,shopname
   from shops s join sales ss on ss.shopsid=s.id
   Grop by id , shopname
   Having count(*) between 10 and 15

拥有分组过滤器，因此您必须使用where代替

Answer 3

如果您只想要id个商店，则不需要join：

select shopsid
from sales
group by shopsid
having count(*) >= 10;