Question

我正在尝试创建一个正则表达式，该表达式将告诉我字符串是否具有/([{0]})([#}])/g，其中可以重复零。一旦确认字符串具有此字符串，我便尝试将其设置为变量，以便可以计算0的数量并将＃替换为另一个数字。我有Regex regex = new Regex(@"\{(0+)(#)\}"); Match match = regex.Match(text); if (match.Success) { int zeros = Regex.Matches(match.Value, "0").Count; }这对检测但不能拉出另一个变量的作品。

编辑：感谢所有人，答案是

reports.get('/xxx/:fileName', async (req, res) => {

  var s3 = new AWS.S3();
  var archiver = require('archiver');

  var filenames = "xxx"
  var str_array = filenames.split(','); 

  for (var i = 0; i < str_array.length; i++) {

    var filename = str_array[i].trim();
    localFileName = './temp/' + filename.substring(filename.indexOf("/") + 1);

    file = fs.createWriteStream(localFileName, {flags: 'a', encoding: 'utf-8',mode: 0666});
    file.on('error', function(e) { console.error(e); });

    s3.getObject({
          Bucket: config.xxx,
          Key: filename
      })
      .on('error', function (err) {
          console.log(err);
      })
      .on('httpData', function (chunk) {
          file.on('open', function(){

            file.write(chunk);
          });
      })
      .on('httpDone', function () {
          file.end();
      })
      .send();
  }
    res.end("Files have been downloaded successfully")

    // create a file to stream archive data to.
    var output = fs.createWriteStream('example.zip');
    var archive = archiver('zip', {
      zlib: { level: 9 } // Sets the compression level.
    });

    // listen for all archive data to be written
    // 'close' event is fired only when a file descriptor is involved
    output.on('close', function() {
      console.log(archive.pointer() + ' total bytes');
      console.log('archiver has been finalized and the output file descriptor has closed.');
    });

    // This event is fired when the data source is drained no matter what was the data source.
    // It is not part of this library but rather from the NodeJS Stream API.
    // @see: https://nodejs.org/api/stream.html#stream_event_end
    output.on('end', function() {
      console.log('Data has been drained');
    });

    // good practice to catch warnings (ie stat failures and other non-blocking errors)
    archive.on('warning', function(err) {
      if (err.code === 'ENOENT') {
        // log warning
      } else {
        // throw error
        throw err;
      }
    });

    // good practice to catch this error explicitly
    archive.on('error', function(err) {
      throw err;
    });

    // pipe archive data to the file
    archive.pipe(output);

    // append files from a sub-directory, putting its contents at the root of archive
    archive.directory('./temp', false);

    // finalize the archive (ie we are done appending files but streams have to finish yet)
    // 'close', 'end' or 'finish' may be fired right after calling this method so register to them beforehand
    archive.finalize();

});

Answer 1

使用此：

\{(0+)(#)\}

字符{

然后出现一个或多个0

一个＃符号

字符}

Live Demo

Answer 2

您超级亲密。您遇到的问题是，因为您的捕获组-( )必须接近零。您还没有严格需要其他捕获组，除非你正在做它的东西。你可以重写你的正则表达式是这样的：

{(0+)#}

{       - match '{'
 (0+)   - match and capture one or more '0'
     #  - match '#'
      } - match '}'

正则表达式查找字符串并将其设置为变量

2 个答案: