在python套接字编程中建立连接后,如何获取客户端的ip地址?

时间:2019-02-07 06:27:34

标签: python python-3.x sockets serversocket peer

我编写了一个套接字程序来发送文件并从套接字接收字符串 我在其中指定了客户端(写了客户端的IP地址) 我想动态获取该客户地址, 我尝试了.getpeername()函数,但出现错误

我尝试了.getpeername()函数,但出现错误

#host = '10.66.227.181'   # fixed ip of one client only
client_socket = socket.socket()
host = client_socket.getpeername()
print(clientip)
port = 8000
print(host,port)
client_socket.connect(host,port)

clientip = socket.gethostname(client_socket.getpeername()) OSError:[WinError 10057]不允许发送或接收数据的请求,因为未连接套接字,并且(当使用sendto调用在数据报套接字上发送时)未提供地址

3 个答案:

答案 0 :(得分:1)

如果未连接UDP套接字,则没有对等体。因此不能有一个对等名称。 如果已连接,则您已经知道如何连接它。

client_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
client_socket.connect(host,port)
host, port = client_socket.getpeername()

答案 1 :(得分:1)

这是“ Python网络编程基础”一书中有关udp套接字(服务器端和客户端)的示例,我认为该示例对您很有用:

import argparse, socket
from datetime import datetime

MAX_BYTES = 65535

def server(port):
    sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    sock.bind(('127.0.0.1', port))
    print('Listening at {}'.format(sock.getsockname()))
    while True:
        data, address = sock.recvfrom(MAX_BYTES)
        text = data.decode('ascii')
        print('The client at {} says {!r}'.format(address, text))
        text = 'Your data was {} bytes long'.format(len(data))
        data = text.encode('ascii')
        sock.sendto(data, address)

def client(port):
    sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    text = 'The time is {}'.format(datetime.now())
    data = text.encode('ascii')
    sock.sendto(data, ('127.0.0.1', port))
    print('The OS assigned me the address {}'.format(sock.getsockname()))
    data, address = sock.recvfrom(MAX_BYTES)  # Danger! See Chapter 2
    text = data.decode('ascii')
    print('The server {} replied {!r}'.format(address, text))

if __name__ == '__main__':
    choices = {'client': client, 'server': server}
    parser = argparse.ArgumentParser(description='Send and receive UDP locally')
    parser.add_argument('role', choices=choices, help='which role to play')
    parser.add_argument('-p', metavar='PORT', type=int, default=1060,
                        help='UDP port (default 1060)')
    args = parser.parse_args()
    function = choices[args.role]
    function(args.p)

source

答案 2 :(得分:0)

由于“主机”术语的原因,上面的答案会让大多数人感到困惑,所以这里有一个更好的答案:

ip_address = my_socket.getpeername()[0]

其中 my_socket 是您已经设置并连接的套接字句柄。