Question

我正在使用CodeIgniter。我遇到错误

Message: `Invalid argument supplied for foreach()`.

让我们详细解释一下。下面是我在控制器中使用的代码

  $send->customer_id=1;//This is just for information

  $fetchdata=$this->Member_model->getAll($send->customer_id);

我得到了输出。我发现与two

相关的1条记录

    Array
(
    [0] => stdClass Object
        (
            [member_id] => 825
            [customer_id] => 123
            [profile_pic] => sbc.jpg
            [first_name] => Shagun
        )

    [1] => stdClass Object
        (
            [member_id] => 
            [customer_id] => 
            [profile_pic] => abfg.jpg
            [first_name] => Mayra 
        )

)

请注意，我没有在第二个数组中获得member_id和customer_id。

下面是我得到输出的模型代码

模型

public function getAll($id){
    $get_s_member = array('members.is_Approved'=>1,'relation_member.primary_customer_id' =>$id);
        $this->db->select('*');
        $this->db->from('members'); 
        $this->db->join('relation_member', 'relation_member.secondary_member_id = members.member_id','LEFT');
        $this->db->join('relations', 'relations.relations_id = relation_member.relation_with_primary_member','LEFT'); 
        $this->db->join('membership_details', 'members.member_id = membership_details.member_id','LEFT'); 
        $this->db->where($get_s_member);
        $query = $this->db->get();
        $res   = $query->result();
     return $res;
  }

为什么我会空着，因为membership_details表中没有记录。我至少需要在成员表中显示所有记录。

我必须在这里传递member_id

$allData['allActivitys']=$this->Member_model->getActivity($member_id);

foreach ($allData['allActivitys'] as $key => $sec_activities) {

}

型号

public function getActivity($gotSecondaryMemberId){
        $getDetails = array('members.member_id'=>$gotSecondaryMemberId);
$result = $this->db->where($getDetails)
                ->select('*')
                ->from('members')
                ->join('relation_member', 'relation_member.secondary_member_id = members.member_id')
                ->join('relations', 'relations.relations_id = relation_member.relation_with_primary_member')
                ->join('member_activity', 'members.member_id = member_activity.member_id','LEFT')
                ->join('activity_name', 'activity_name.activity_name_id = member_activity.activity_id','LEFT')
                ->get()
                ->result();

    if($result)
    {
         return $result;  
    }
    else 
    {
       return 0;  
    }

  }

但是它只获取第一个数组，而在第二个错误中则是错误消息：Invalid argument supplied for foreach()。

Answer 1

您只需要在if循环之前添加一些foreach条件

$allData['allActivitys']=$this->Member_model->getActivity($member_id);
if(!empty($allData) && isset($allData['allActivitys'] )){
    foreach ($allData['allActivitys'] as $key => $sec_activities) {
        //your code goes here
    }
}

从模型中获取数据时为foreach提供的参数无效

1 个答案: