Question

我正在使用CodeIgniter。我正在从控制器获取数据。

型号代码

 $select_filter_status=$parameters['select_filter_status'];
 $select_filter_action= $parameters['select_filter_action'];

if(($select_filter_status=='') && ($select_filter_action=='')){
       $where_2=" "; // I don't have any condition here. I have to display all the records

}
else if(($select_filter_status=='') || ($select_filter_action=='')){

        if ($select_filter_action=='') {
            $where_2="product_order.o_order_status=".$select_filter_status;
      }
      else{
            $where_2="product_order.o_order_status_confirm=".$select_filter_action;
      }
}
else{
        $where_2="product_order.o_order_status=".$select_filter_status." and product_order.o_order_status_confirm=".$select_filter_action;
  }




$this->db->select("*");
$this->db->from('tbl_customer');
$this->db->join('tbl_customer_billing', 'tbl_customer.cust_id=tbl_customer_billing.c_b_id', 'LEFT');
$this->db->join('tbl_customer_shipping', 'tbl_customer.cust_id=tbl_customer_shipping.cust_id', 'LEFT');
$this->db->where($com_report);
$this->db->where($where_2); // I want to remove this where clause when there is empty status and action
$this->db->order_by('product_order.o_date_of_added','DESC');
$query = $this->db->get();
$result = $query->result();

我的问题是，查询中有两个where子句，如果发现where condition和$select_filter_status为空，则必须删除第二个$select_filter_action。

有什么方法可以删除where子句吗？或者我必须使用类似的东西

if(){
//with two where clause
}
else{
//with one where clasue
}

Answer 1

在这种情况下，您只能简单地放置一个。它将为您工作。

if (!empty($where_2){
   $this->db->where($where_2);
}

如果$ where_2不为空，它将执行第二个where条件，如果为空，它将忽略第二个where。

或者您可以像这样连接查询字符串以仅使用一个查询子句

$com_report = $com_report . " " . $where_2;

现在不需要第二个where子句希望它对您有用

Answer 2

您必须在主查询中传递where_2查询。在$ com_report查询中添加变量$ where_2

if(($select_filter_status=='') && ($select_filter_action=='')){
       $where_2=" "; // I don't have any condition here. I have to display all the records

}
else if(($select_filter_status=='') || ($select_filter_action=='')){

        if ($select_filter_action=='') {
            $where_2="and product_order.o_order_status=".$select_filter_status;
      }
      else{
            $where_2="and product_order.o_order_status_confirm=".$select_filter_action;
      }
}
else{
        $where_2="and product_order.o_order_status=".$select_filter_status." and product_order.o_order_status_confirm=".$select_filter_action;
  }

现在

$com_report ='your where statements ' .$where_2 ;

立即将其传递给查询生成器

$this->db->where($com_report);

我希望它对您有用

Answer 3

是的，您可以基于Codeigniter中的条件添加where子句，像这样

$this->db->select("*");
$this->db->from('tbl_customer');
$this->db->join('tbl_customer_billing', 'tbl_customer.cust_id=tbl_customer_billing.c_b_id', 'LEFT');
$this->db->join('tbl_customer_shipping', 'tbl_customer.cust_id=tbl_customer_shipping.cust_id', 'LEFT');
$this->db->where($com_report);
if(!empty($select_filter_status) AND !empty($select_filter_action)){
    $this->db->where($where_2); 
}


$this->db->order_by('product_order.o_date_of_added','DESC');
$query = $this->db->get();
$result = $query->result();

有什么方法可以使用逻辑从查询中删除where子句？

3 个答案: