Question

我在实现2个参数时遇到问题：http://localhost:8080/SMSBlast/SequenceID?SequenceID=2&MobilePhone=85261415223

如何使用两列SequenceID和MobilePhone进行查询以获得SequenceID=2&MobilePhone=85261415223，我尝试了很多方法，但仍然无法使用

package main

import (
    "database/sql"
    "fmt"
    _ "github.com/denisenkom/go-mssqldb"
    "github.com/gin-gonic/gin"
    "net/http"
    "time"
)

func main()  {
    db, err :=  sql.Open("sqlserver","sqlserver://sa:@localhost:1433?database=CONFINS&connection+timeout=30")
    if err != nil{
        fmt.Print(err.Error())
    }


    err = db.Ping()

    if err != nil {
        fmt.Print(err.Error())
    }
    defer db.Close()

    type SMSBlast struct {
        SequenceID  int
        MobilePhone string
        Output  string
        WillBeSentDate *time.Time
        SentDate *time.Time
        Status *string
        DtmUpd *time.Time
    }

    router := gin.Default()

    //Get a SMSBlast  detail
    router.POST("/SMSBlast/:SequenceID", func(context *gin.Context) {
        var(
            smsblast SMSBlast
            result gin.H
        )

    SequenceID := context.Param("SequenceID")
    MobilePhone := context.Param("MobilePhone")

        err := db.QueryRow("SELECT SequenceID,MobilePhone,Output,WillBeSentDate, SentDate, Status, DtmUpd FROM  SMSBlast2 Where SequenceID = ? AND MobilePhone = ? "+SequenceID , MobilePhone).Scan(&smsblast.SequenceID, &smsblast.MobilePhone, &smsblast.Output, &smsblast.WillBeSentDate, &smsblast.SentDate, &smsblast.Status, &smsblast.DtmUpd)
        //fmt.Println(row)
        fmt.Println(err)
        //err = row.Scan(&smsblast.SequenceID, &smsblast.MobilePhone, &smsblast.Output, &smsblast.WillBeSentDate, &smsblast.SentDate, &smsblast.Status, &smsblast.DtmUpd)

        if err != nil{
            //if no results send null
            result = gin.H{
                "result": nil,
                "count":  0,
            }
            }else{
                result = gin.H{
                    "result" : smsblast,
                    "count" : 1,
                }
            }

        context.JSON(http.StatusOK, result)
    })

Answer 1

您的语法不正确。试试这个：

err := db.QueryRow("SELECT SequenceID,MobilePhone,Output,WillBeSentDate, SentDate, Status, DtmUpd FROM  SMSBlast2 Where SequenceID = $1 AND MobilePhone = $2", SequenceID, MobilePhone).Scan(&smsblast.SequenceID, &smsblast.MobilePhone, &smsblast.Output, &smsblast.WillBeSentDate, &smsblast.SentDate, &smsblast.Status, &smsblast.DtmUpd)

编辑：

该查询包含枚举为$1，$2等的占位符。这些占位符用于包含作为参数的变量。在您的评论中，您将$1替换为$3。那不是它的工作原理。将其保留为$1，将值存储在SequenceID变量中，然后将该变量传递给QueryRow。

这是一个简化的示例，以说明：

SequenceID := 3
err := db.QueryRow("SELECT * FROM SMSBlast2 WHERE SequenceID = $1", SequenceID).Scan(...)

现在有两个参数：

SequenceID := 3
MobilePhone := "85261415223"
err := db.QueryRow("SELECT * FROM SMSBlast2 WHERE SequenceID = $1 AND MobilePhone = $2", SequenceID, MobilePhone).Scan(...)

Answer 2

请尝试使用Query()，例如here：

SequenceID := context.Query("SequenceID")
MobilePhone := context.Query("MobilePhone")

如何实现2参数，以及如何通过QueryRow实现参数SequenceID和MobilePhone

2 个答案: