Question

嗨，我想按对象转换为数组，但我不知道该怎么做。

对象

{ stops: [ 'Route1', 'Route2' ], time: [ '12:00 am', '12:30 am', '01:00 am', '01:30 am', '02:00 am' ], _id: 5c636357bc92ec0e44a44946}

如何解析time: [ '12:00 am', '12:30 am', '01:00 am', '01:30 am', '02:00 am' ]，就像这样。

数组

[ '12:00 am', '12:30 am', '01:00 am', '01:30 am', '02:00 am' ]

Answer 1

使用。访问时间属性的符号

var obj={ stops: [ 'Route1', 'Route2' ], time: [ '12:00 am', '12:30 am', '01:00 am', '01:30 am', '02:00 am' ], _id: '5c636357bc92ec0e44a44946'}
console.log(obj.time)

Answer 2

用于将所有内容转换为数组

ReadInteger proc
TryAgain:
    call    _getchar          ; read input from stdin; return result in EAX
    cmp     eax, 48           ; \ if (input < '0')
    jl      TryAgain          ; /  jump to TryAgain
    cmp     eax, 57           ; \ if (input > '9')
    jg      TryAgain          ; /  jump to TryAgain
    sub     eax, 48           ; input -= '0'
    ret
ReadInteger endp

multi proc
    push   esi
    push   ebx
    push   edi

    call   ReadInteger
    mov    esi, eax

    call   ReadInteger
    mov    ebx, eax

    call   ReadInteger
    mov    edi, eax

    call   ReadInteger
    add    eax, esi
    add    eax, ebx
    sub    eax, edi
    mul    ebx
    mov    [foo], eax

    pop    edi
    pop    ebx
    pop    esi

    ret
multi endp

如果您只想转换时间属性，那么

ReadConsoleInput

如何解析对象并将其转换为数组

2 个答案: