Question

我是新来的爬行者，我试图从https://www.lacuarta.com/中提取一些新闻，也只是与标签san-valentin相匹配的新闻。

该网页只是带有新闻图片的标题，如果您想阅读该新闻，则必须单击该新闻，这会将ypu带到该故事的页面（https://www.lacuarta.com/etiqueta/san-valentin/）

所以，我想我要采取的步骤是：

转到与我想要的标签匹配的页面，在这种情况下为san-valentin
从新闻中提取网址
转到新闻页面
提取我想要的数据

我已经有了要点1和2：

import scrapy

class SpiderTags(scrapy.Spider):
    name = "SpiderTags"

    def start_requests(self):
        url = 'https://www.lacuarta.com/etiqueta/'
        tag = getattr(self, 'tag', None)
        if tag is not None:
            url = url + 'etiqueta/' + tag
        yield scrapy.Request(url, self.parse)

    def parse(self, response):
        for url in response.css("h4.normal a::attr(href)"):
            yield{
                "link:": url.get()
            }

到目前为止，我有新闻的链接，现在我不知道如何输入该新闻以提取所需的数据，然后返回到原始网页转到第2页并重复所有操作

PD：我想要的信息已经知道如何获取

标题：response.css("title::text").get()
故事：response.css("div.col-md-11 p::text").getall()
作者：response.css("div.col-sm-6 h4 a::text").getall()
日期：response.css("div.col-sm-6 h4 small span::text").getall()

Answer 1

您需要yield新的Request以便关注链接。例如：

def parse(self, response):
    for url in response.css("h4.normal a::attr(href)"):
        # This will get the URL value, not follow it:
        # yield{
        #     "link:": url.get()
        # }
        # This will follow the URL:
        yield scrapy.Request(url.get(), self.parse_news_item)

def parse_news_item(self, response):
    # Extract things from the news item page.
    yield {
        'Title': response.css("title::text").get(),
        'Story': response.css("div.col-md-11 p::text").getall(),
        'Author': response.css("div.col-sm-6 h4 a::text").getall(),
        'Date': response.css("div.col-sm-6 h4 small span::text").getall(),
    }

Answer 2

import scrapy
from scrapy.spiders import CrawlSpider

class SpiderName(CrawlSpider):
    name = 'spidername'
    allowed_domains = ['lacuarta.com']
    start_urls = ['https://www.lacuarta.com/etiqueta/san-valentin/']

    def parse(self, response):
        for item in response.xpath('//article[@class="archive-article modulo-fila"]'):
        # maybe you need more data whithin `item`
            post_url = item.xpath('.//h4/a/@href').extract_first()
            yield response.follow(post_url, callback=self.post_parse)

        next_page = response.xpath('//li[@class="active"]/following-sibling::li/a/@href').extract_first()
        if next_page:
            yield response.follow(next_page, callback=self.parse)

    def post_parse(self, response):
        title = response.xpath('//h1/text()').extract_first()
        story = response.xpath('//div[@id="ambideXtro"]/child::*').extract()
        author = response.xpath('//div[@class="col-sm-6 m-top-10"]/h4/a/text()').extract_first()
        date = response.xpath('//span[@class="ltpicto-calendar"]').extract_first()
        yield {'title': title, 'story': story, 'author': author, 'date': date}

跟踪新闻链接，抓狂

2 个答案: