Question

我有一个大表（6+百万行），我想添加一个自动递增的整数列sid，其中sid是基于{{1 }}。换句话说，基于ORDER BY inserted_at ASC的最旧记录将被设置为inserted_at，而最新记录将是总记录数。关于如何处理此问题的任何提示？

Answer 1

添加一个sid列和UPDATE SET ... FROM ... WHERE：

UPDATE test
SET sid = t.rownum
FROM (SELECT id, row_number() OVER (ORDER BY inserted_at ASC) as rownum
    FROM test) t
WHERE test.id = t.id

请注意，这依赖于主键id。（如果您的表还没有主键，则必须先创建一个。）

例如，

-- create test table
DROP TABLE IF EXISTS test;
CREATE TABLE test (
    id int PRIMARY KEY GENERATED BY DEFAULT AS IDENTITY
    , foo text
    , inserted_at TIMESTAMP WITH TIME ZONE DEFAULT CURRENT_TIMESTAMP
);
INSERT INTO test (foo, inserted_at) VALUES
('XYZ', '2019-02-14 00:00:00-00')
, ('DEF', '2010-02-14 00:00:00-00')
, ('ABC', '2000-02-14 00:00:00-00');

-- +----+-----+------------------------+
-- | id | foo |      inserted_at       |
-- +----+-----+------------------------+
-- |  1 | XYZ | 2019-02-13 19:00:00-05 |
-- |  2 | DEF | 2010-02-13 19:00:00-05 |
-- |  3 | ABC | 2000-02-13 19:00:00-05 |
-- +----+-----+------------------------+

ALTER TABLE test ADD COLUMN sid INT;

UPDATE test
SET sid = t.rownum
FROM (SELECT id, row_number() OVER (ORDER BY inserted_at ASC) as rownum
    FROM test) t
WHERE test.id = t.id

收益

+----+-----+------------------------+-----+
| id | foo |      inserted_at       | sid |
+----+-----+------------------------+-----+
|  3 | ABC | 2000-02-13 19:00:00-05 |   1 |
|  2 | DEF | 2010-02-13 19:00:00-05 |   2 |
|  1 | XYZ | 2019-02-13 19:00:00-05 |   3 |
+----+-----+------------------------+-----+

最后，将sid序列为（or, better, an IDENTITY column）：

ALTER TABLE test ALTER COLUMN sid SET NOT NULL;
-- IDENTITY fixes certain issue which may arise with SERIAL
ALTER TABLE test ALTER COLUMN sid ADD GENERATED BY DEFAULT AS IDENTITY;
-- ALTER TABLE test ALTER COLUMN sid SERIAL;

PostgreSQL使用基于ORDER BY的值将SERIAL列添加到现有表中

1 个答案: