Question

我有两个表（A）和（B），在不同的日期几乎具有相同的信息。

表（A）

+----+------------+----------+-------+
|ID  | Date       | Status   | Amount|
+----+------------+----------+-------+
| A1 | 01/14/2011 | Received |15     |
| A2 | 01/18/2011 | Received |65     |
| T3 | 01/9/2011  | Received |85     |
| X7 | 02/16/2011 | Received |35     |
| A5 | 01/3/2011  | Received |10     |
+----+------------+----------+-------+

表（B）

+----+------------+----------+-------+
|ID  | Date       | Status   | Amount|
+----+------------+----------+-------+
| A1 | 03/31/2012 | Approved |15     |
| A2 | 03/31/2012 | Denied   |65     |
| A3 | 03/31/2012 | Approved |85     |
| A7 | 03/31/2012 | Received |35     |
| A5 | 03/31/2012 | pending  |10     |
+----+------------+----------+-------+

我正在尝试将它们合并，以获得新的表（结果），如下所示：

表格（结果）

+----+------------+----------+-------+
|ID  | Date       | Status   | Amount|
+----+------------+----------+-------+
| A1 | 01/14/2011 | Received |15     |
| A1 | 03/31/2012 | Approved |15     |
| A2 | 01/18/2011 | Received |65     |
| A2 | 03/31/2012 | Denied   |65     |
| A5 | 01/3/2011  | Received |10     |
| A5 | 03/31/2012 | pending  |10     |
+----+------------+----------+-------+

我使用了以下代码：

SELECT *
FROM table1
JOIN table2
ON table1.id = table2.id
ORDER BY table1.id;

这是结果：

+----+------------+----------+-------+------------+------------+---------+
| ID | Date       | Status   | Amount| Date_1     | Status_1   | Amount_1|
+----+------------+----------+-------+------------+------------+---------+
| A1 | 01/14/2011 | Received |15     |03/31/2012  | Approved   |15       |
+----+------------+----------+-------+------------+------------+---------+

工作正常，但这不是我想要的。我不想并排重复的列。我当时正在考虑使用INSERT INTO或UNION ALL，但不确定。

Answer 1

在UNION中，每个表仅包含其他表中具有相应行的行：

SELECT * FROM TableA a
WHERE EXISTS (
  SELECT 1 FROM TableB
  WHERE ID = a.ID AND Amount = a.Amount AND Status <> a.Status
)
UNION
SELECT * FROM TableB b
WHERE EXISTS (
  SELECT 1 FROM TableA
  WHERE ID = b.ID AND Amount = b.Amount AND Status <> b.Status
)
ORDER BY ID;

我不确定条件Amount = x.Amount。也许您想删除它。

Answer 2

这是一个简单的联合所有查询来完成工作：

select * from a where id in (select id from b)
union all
select * from b where id in (select id from a)
order by id, date;

Answer 3

select x.id, x.status, x.amount, y.status, y.amount
from 
(
select 'A1' id, 'received' status, 15 amount from dual
union all
select 'A2' id, 'received' status, 65 amount from dual
) x,
 (
select 'A1' id, 'approved' status, 15 amount from dual
union all
select 'A2' id, 'denied' status, 65 amount from dual
) y
where x.id = y.id

希望有帮助！

Answer 4

尝试一下：

<class 'numpy.ndarray'>
[[9.630769e-01 4.302222e-02 8.238154e-02]
 [7.661538e-01 3.153453e-01 4.497161e-01]
 [5.753846e-01 6.559556e-01 8.274414e-01]
 [4.027350e-01 9.705709e-01 1.175706e+00]
 ...
]

Answer 5

如果目的（您尚未真正描述的）是报告来自两个表中都存在ID的任一表中的行，那么您可能想要这样做：

select id, somedate, status, amount
from   ( select id, somedate, status, amount from table_a
         union all
         select id, somedate, status, amount from table_b )
where  id in
       ( select id from table_a
         intersect
         select id from table_b )

Answer 6

使用UNION：

SELECT ID, Date, Status, Amount
FROM table1
UNION
SELECT ID, Date, Status, Amount
from table2
ORDER BY ID;

如何将两张桌子合为一体？

6 个答案: