我有一个网页,可让您浏览不同的工作机会,这些机会保存在名为“ jobs”
的MySQL表中“职位” 有不同的列,其中之一是正常职位的 “基本” ,而 ” op2” (高级职位)。
执行搜索时,我试图在搜索结果中显示这两个类别,但是我只能显示一个,而不能两个都显示。
我能够使用以下方式显示这两项工作:
$premium_jobs = Posts::where('title', 'like', '%' . $request->q . '%')->where('type', 'op2')->where('status', 'active')->orderBy('id', 'desc')->take(3)->get();
但是,当使用过滤器搜索特定单词时,它适用于基本作业,但显示所有高级作业而无需应用任何过滤器。
一些无效的查询:
搜索基本职位,但无论搜索什么内容,始终显示所有高级职位:
$premium_jobs = Posts::where('title', 'like', '%' . $request->q . '%')->where('type', 'op2')->where('status', 'active')->orderBy('id', 'desc')->take(3)->get();
不显示高级职位,仅显示基本职位:
$premium_jobs = Posts::where('title', 'like', '%' . $request->q . '%')->where('type', 'op2')->where('type', 'basic')->where('status', 'active')->orderBy('id', 'desc')->take(3)->get();
不显示基本作业,仅显示高级作业:
$premium_jobs = $jobs->where('type', 'op2')->where('status', 'active')->paginate(15);
显示高级职位和基本职位,但也显示基本职位的重复作为高级职位:
$premium_jobs = $jobs->where('status', 'active')->paginate(15);
控制器:
<?php
class SearchController extends Controller
{
public function index(Request $request){
$jobs = new Posts();
if ($request->has('q')) {
$jobs = $jobs->where('title', 'like', '%' . $request->q . '%');
}
if (!empty($request->city)) {
$city = Cities::where('name', $request->city)->first();
$jobs = $jobs->where('city_id', $city->id);
}
if (!empty($request->min_salary)) {
$jobs = $jobs->where('salary', '>', $request->min_salary);
}
if (!empty($request->jt)) {
$job_type = JobTypes::where('name', $request->jt)->first();
$jobs = $jobs->where('job_type_id', $job_type->id);
}
if (!empty($request->ex)) {
$jobs = $jobs->where('experience', $request->ex);
}
if (!empty($request->cat)) {
$category = Categories::where('name', $request->cat)->first();
$jobs = $jobs->where('cat_id', $category->id);
}
// PREMIUM JOBS
$premium_jobs = $jobs->where('status', 'active')->paginate(15);
// BASIC JOBS
$basic_jobs = $jobs->where('type', 'basic')->where('status', 'active')->paginate(15);
$cities = Cities::all();
$job_types = JobTypes::all();
$categories = Categories::all();
return view('search.index', compact('basic_jobs', 'premium_jobs', 'request', 'cities', 'job_types', 'categories'));
}
?>
任何见识将不胜感激!
谢谢。
答案 0 :(得分:0)
您还有其他工作类型吗? 如果没有尝试
Posts::where('title', 'like', '%' . $request->q . '%')->where('status', 'active')->orderBy('id', 'desc')->take(3)->get();
答案 1 :(得分:0)
<?php
// To get both the jobs :
$allJobs = $jobs->where('status', 'active')->paginate(15);
// To get al basic jobs
$allBasicJobs = $jobs->where('status', 'active')->where('type', 'basic')->paginate(15);
// To get all premium jobs
$allBasicJobs = $jobs->where('status', 'active')->where('type', 'op2')->paginate(15);
// To search title in basic jobs but get all premier jobs
$filteredBasicJobsAllPremiumJobs = $jobs->where('status', 'active')
->where('type', 'op2')
->orWhere(function($q) use($request){
return $q->where('type', 'basic')
->where('title', 'like', '%' . $request->q . '%');
})
->paginate(15);
// To search title in permium jobs but get all basic jobs
$filteredPremiumJobsAllBasicJobs = $jobs->where('status', 'active')
->where('type', 'basic')
->orWhere(function($q) use($request){
return $q->where('type', 'op2')
->where('title', 'like', '%' . $request->q . '%');
})
->paginate(15);
// To search title in both basic and premium jobs
$filteredJobs = $jobs->where('status', 'active')
->where('title', 'like', '%' . $request->q . '%')
->paginate(15);