Java ConcurrentModificationException，而无需对其进行迭代

Question

我正在尝试在没有接口atm的情况下编写Java Domino游戏，并且遇到了并发修改异常，并且在迭代时未添加或删除。而且，当我遍历它们时，我只是在打印它们的值

我设计了一个类系统，其中的类播放器具有列表。在本课程中，我删除每个玩家的多米诺骨牌。我已经尝试过使用迭代器进行迭代，但是看不到任何更改。

do {
            if (counter >= players.size()) {
                counter = 0;
            }
            Player p = players.get(counter);
            System.out.println("It is " + p.getName() + " turn");
            if (lastdominoes.size() == 0) {
                System.out.println("There is no dominoes in the table. Please make a move:");
            } else {
                for (Entry<String, Domino> e : lastdominoes.entrySet()) {
                    System.out.print("The last dominoes played are:");
                    System.out.print(e.getValue().toString());
                }
            }
            System.out.println();
            System.out.println("Your dominoes are:");
            int numberaux = 0;
            String dominoesnumber = "";
            Iterator<Domino> iteratordominoes = p.getDominoes().iterator();
            while (iteratordominoes.hasNext()) {
                Domino d = iteratordominoes.next();
                System.out.print(d.toString());
                dominoesnumber += " " + numberaux + "  ";
                numberaux++;
            }
            System.out.println();
            System.out.printf(dominoesnumber);
            System.out.println("Please choose a domino:");
            int choosenDominoNumber = scan.nextInt();
            System.out.println("You are about to move the Domino" + p.getDominoes().get(choosenDominoNumber).toString());
            placeaDomino(p, p.getDominoes().get(choosenDominoNumber));
            System.out.printf("\n\n");
            if(p.endofGame()){endofgame=true;}
            counter++;
        } while (!endofgame);

这是Domino方法的地方

 public boolean placeaDomino(Player p, Domino d) {
        if (playedDominoes.isEmpty()) {
            playedDominoes.add(d);
            unplayeddominoes.remove(d);
            lastdominoes.put(d.getDirection(), d);
            p.makeaMove(d);
            return true;
        } else if (lastdominoes.get(d.getDirection()).match(d)) {
            playedDominoes.add(d);
            unplayeddominoes.remove(d);
            lastdominoes.put(d.getDirection(), d);
            p.makeaMove(d);
            return true;
        }
        return false;
    }

p.makeaMove基本上只是删除多米诺骨牌

public void makeaMove(Domino d){
        this.dominoes.remove(d);
    }

这是程序的执行，因此更加清晰

 How many players you want to play with
2
There are 2 players in this table
It is Player 1 turn
There is no dominoes in the table. Please make a move:

Your dominoes are:
3/5 2/2 2/6 3/3 5/3 4/5 1/6 
 0   1   2   3   4   5   6  Please choose a domino:
2
You are about to move the Domino2/6 

Then exception occurs
Exception in thread "main" java.util.ConcurrentModificationException
    at java.util.ArrayList$SubList.checkForComodification(ArrayList.java:1239)
    at java.util.ArrayList$SubList.listIterator(ArrayList.java:1099)
    at java.util.AbstractList.listIterator(AbstractList.java:299)
    at java.util.ArrayList$SubList.iterator(ArrayList.java:1095)
    at java.util.AbstractCollection.remove(AbstractCollection.java:282)
    at dominolibrary.Player.makeaMove(Player.java:72)
    at dominolibrary.Table.placeaDomino(Table.java:116)
    at dominolibrary.Table.<init>(Table.java:79)
    at dominolibrary.DominoLibrary.main(DominoLibrary.java:18)
Java Result: 1

我想要在每次迭代中做的是从玩家的区域中删除一个多米诺骨牌，直到一个玩家列表为空。