Question

我正在尝试计算所有五分钟期间的总和，每个区域IP的流量总和（以gbps为单位）。

我是BigQuery的新手，因此通过查看其他示例，我尝试了以下操作：

deactivate(_:)

我希望输出为：

WITH `project.dataset.test` AS (
  SELECT '01/01/2019 12:30' time, '192.168.10.1' ip_address, 10 network, 1 gbps UNION ALL
  SELECT '01/01/2019 12:30', '192.168.10.2', 11, 2 UNION ALL
  SELECT '01/01/2019 12:30', '192.168.10.3', 12, 3 UNION ALL
  SELECT '01/01/2019 12:35', '192.168.10.1', 10, 1 UNION ALL
  SELECT '01/01/2019 12:35', '192.168.10.2', 11, 2 UNION ALL
  SELECT '01/01/2019 12:35', '192.168.10.3', 12, 3 UNION ALL
  SELECT '01/01/2019 12:40', '192.168.10.1', 10, 1 UNION ALL
  SELECT '01/01/2019 12:40', '192.168.10.2', 11, 2 UNION ALL
  SELECT '01/01/2019 12:40', '192.168.10.3', 12, 3
  ),
ip AS (
  SELECT DISTINCT (ip_address) ip_address
  FROM `project.dataset.test`
),
qualified AS (
SELECT ip_address, network, ARRAY_AGG (gbps ORDER BY ip_address DESC LIMIT 1)[SAFE_OFFSET(0)] gbps
FROM `project.dataset.test`
GROUP BY ip_address, network
)
SELECT ip_address, network, SUM(gbps)gbps
FROM (
SELECT d.ip_address ip_address, network, ARRAY_AGG (gbps ORDER BY q.ip_address DESC LIMIT 1)[SAFE_OFFSET(0)] gbps
FROM ip d
JOIN qualified q
ON q.ip_address = d.ip_address
GROUP BY ip_address, network
)
group BY ip_address, network
ORDER BY gbps DESC

实际的输出是：

Row     ip_address      network   gbps  
1       192.168.10.3    12        9
2       192.168.10.2    11        6
3       192.168.10.1    10        3

我在做什么错？不管5分钟间隔和/或网络数量如何，如何选择不同IP的总和？费伊，我要整理成千上万的行，这只是我正在处理的示例。

Answer 1

无论5分钟和/或5分钟的网络数量如何，如何选择不同IP的总和？

以下示例适用于BigQuery Standatd SQL

#standardSQL
WITH `project.dataset.test` AS (
  SELECT '01/01/2019 12:30' time, '192.168.10.1' ip_address, 10 network, 1 gbps UNION ALL
  SELECT '01/01/2019 12:30', '192.168.10.2', 11, 2 UNION ALL
  SELECT '01/01/2019 12:30', '192.168.10.3', 12, 3 UNION ALL
  SELECT '01/01/2019 12:35', '192.168.10.1', 10, 1 UNION ALL
  SELECT '01/01/2019 12:35', '192.168.10.2', 11, 2 UNION ALL
  SELECT '01/01/2019 12:35', '192.168.10.3', 12, 3 UNION ALL
  SELECT '01/01/2019 12:40', '192.168.10.1', 10, 1 UNION ALL
  SELECT '01/01/2019 12:40', '192.168.10.2', 11, 2 UNION ALL
  SELECT '01/01/2019 12:40', '192.168.10.3', 12, 3
)
SELECT ip_address, network, SUM(gbps) gbps
FROM `project.dataset.test`
GROUP BY ip_address, network

有结果

Row ip_address      network gbps     
1   192.168.10.3    12      9    
2   192.168.10.2    11      6    
3   192.168.10.1    10      3

BigQuery和标准SQL：数组中每个distnict字段的聚合

1 个答案: