Question

如果我有一个包含多个子文件夹的文件夹，则每个文件夹都具有相同的结构sub1，sub2和sub3：

├─a
│  ├─sub1
│  ├─sub2
│  └─sub3
├─b
│  ├─sub1
│  ├─sub2
│  └─sub3
└─c
    ├─sub1
    ├─sub2
    └─sub3
...

如果内部有图像文件，我想复制sub1和sub2，并在保留目录树结构的同时忽略其他子文件夹（sub3...）。这是预期的结果：

├─a
│  ├─sub1
│  └─sub2
├─b
│  ├─sub1
│  └─sub2
└─c
    ├─sub1
    └─sub2
...

我应该怎么做才能获得预期的结果？我尝试使用以下代码，但只复制了sub1，sub2和sub3，我得到了TypeError: copy() takes no arguments (1 given)。

感谢@PrasPJ。

import os
import os.path
import shutil
import fnmatch

src_dir= ['C:/Users/User/Desktop/source/input']      # List of source dirs
included_subdirs = ['sub1', 'sub2']        # subdir to include from copy
dst_dir = 'C:/Users/User/Desktop/source/output'     # folder for the destination of the copy
for root_path in src_dir:
    #print(root_path)
    for root, dirs, files in os.walk(root_path): # recurse walking
        for dir in included_subdirs:
            #print(dir)
            if dir in dirs:
                source = os.path.join(root,dir)
                f_dst = source.replace(root_path, dst_dir)
                print (source, f_dst)
                for file in os.listdir(source):
                    print(file)
                    if file.endswith(".jpg") or file.endswith(".jpeg"):
                        shutil.copytree(source, f_dst)

与参考相关：

https://www.daniweb.com/programming/software-development/threads/356380/how-to-copy-folders-directories-using-python

Python shutil copytree: use ignore function to keep specific files types

How to copy contents of a subdirectory in python

Answer 1

嗨，您正在尝试使用词典的复制功能，这是错误的

import os
import os.path
import shutil
import fnmatch

list_of_dirs_to_copy = ['C:/Users/User/Desktop/test/input'] # List of source dirs
included_subdirs = ['sub1', 'sub2']  # subdir to include from copy
dest_dir = 'C:/Users/User/Desktop/test/output'     # folder for the destination of the copy
for root_path in list_of_dirs_to_copy:
    print(root_path)
    for root, dirs, files in os.walk(root_path): # recurse walking
        for dir in included_subdirs:
            print(dir)
            if dir in dirs:
                source = os.path.join(root,dir)
                f_dest = source.replace(root_path, dest_dir)
                print source, f_dest 
                shutil.copytree(source,f_dest)

Answer 2

import os
import os.path
import shutil
import fnmatch

list_of_dirs_to_copy = ['C:/Users/User/Desktop/test/input'] # List of source dirs
included_subdirs = ['sub1', 'sub2']  # subdir to include from copy
dest_dir = 'C:/Users/User/Desktop/test/output'     # folder for the destination of the copy
for root_path in list_of_dirs_to_copy:
    print(root_path)
    for root, dirs, files in os.walk(root_path): # recurse walking
        for dir in included_subdirs:
            print(dir)
            if dir in dirs:
                source = os.path.join(root,dir)
                for f in os.listdir(source):
                    print os.path.join(source,f)
                    if os.path.isfile(os.path.join(source,f)) and (f.endswith("jpg") or f.endswith("jpeg")): 
                        f_dest = source.replace(root_path, dest_dir)
                        print source, f_dest 
                        shutil.copytree(source,f_dest)
                        break # found any one matching file

Answer 3

这是更新

for root_path in list_of_dirs_to_copy:
    for root, dirs, files in os.walk(root_path): # recurse walking
        path_to_copy = {}
        for dir in included_subdirs:
            if dir in dirs:
                source = os.path.join(root,dir)
                for f in os.listdir(source):
                    if os.path.isfile(os.path.join(source,f)) and (f.endswith("jpg") or f.endswith("jpeg")):
                        f_dest = source.replace(root_path, dest_dir)
                        path_to_copy.update({source: f_dest})
        if len(path_to_copy) == len(included_subdirs):
            for source, f_dest in path_to_copy.iteritems():
                shutil.copytree(source,f_dest)

使用Python按名称复制特定子目录

3 个答案: