Question

我的功能有问题。

我创建了一个函数，该函数可以读取DB中的表并从一列中找到DISTINCT值。

第一个循环是循环遍历DISTINCT值第二个循环是从另一列获取值。

当我从第二个循环中收集数据时，一切似乎都很好，但是当我尝试在循环外回显变量时，该值已更改为我不知道其来源。

我对PHP相当陌生，无法在任何地方找到解决方案。

功能：

function region_tilbehor() {
include '../db.php'; 
global $fdato;
global $tdato;

$query_tilbehor = "SELECT DISTINCT region FROM salg";
$result_tilbehor = mysqli_query($connect, $query_tilbehor);

while($row_tilbehor = mysqli_fetch_array($result_tilbehor)) {
    $region = $row_tilbehor['region'];

    $sql_tilbehor = "SELECT * FROM salg WHERE region='$region' AND kategori LIKE 'tilbehor' AND dato BETWEEN '$fdato' AND '$tdato'";
    $kjor_tilbehor = mysqli_query($connect, $sql_tilbehor);
    $qty = 0;
    while ($num = mysqli_fetch_array($kjor_tilbehor)) {
        $sum = $num['belop'];
        $qty += $sum;

    }
    $qty .= ", ";

    echo $qty; //gives this: 54726, 14313, 23689, 5885, 39783,
               //This is the value i want to return from function.

}
echo "same variable outside loop: " .$qty; //Gives this: same variable outside loop: 39783, 

return $qty;
}

Answer 1

function region_tilbehor() {
include '../db.php'; 
global $fdato;
global $tdato;
$sumArray = [];
$query_tilbehor = "SELECT DISTINCT region FROM salg";
$result_tilbehor = mysqli_query($connect, $query_tilbehor);

while($row_tilbehor = mysqli_fetch_array($result_tilbehor)) {
    $region = $row_tilbehor['region'];

    $sql_tilbehor = "SELECT * FROM salg WHERE region='$region' AND kategori LIKE 'tilbehor' AND dato BETWEEN '$fdato' AND '$tdato'";
    $kjor_tilbehor = mysqli_query($connect, $sql_tilbehor);
    $qty = 0;
    while ($num = mysqli_fetch_array($kjor_tilbehor)) {
        $sum = $num['belop'];
        $qty += $sum;

    }
    $qty .= ", ";
    array_push($sumArray,$qty); 
    echo $qty; //gives this: 54726, 14313, 23689, 5885, 39783,
               //This is the value i want to return from function.

}
print_R($sumArray);die; //Gives this: same variable outside loop: 39783, 

return $qty;
}

变量在函数内部的while循环后更改值

1 个答案: