Swagger在请求正文中显示了额外的参数

时间:2019-02-21 12:10:26

标签: swagger swagger-ui swagger-2.0 swagger-codegen swagger-editor

我们正在使用2.7.0版的springfox-swagger-ui和springfox-swagger2。

post api具有以下签名:

@ApiOperation("Edits information about employees")
@PostMapping(path = "/employee/edit", headers = EndPoints.VERSION_1)
@ApiResponses(value = {
    @ApiResponse(code = 409, message = "Data mismatch"),
    @ApiResponse(code = 400, message = "Invalid data passed")
})
public ResponseEntity<Employee> manageEmployee(
        @RequestHeader("employeeId") final String iEmployeeId,
        @RequestBody(required = true) @Valid final Employee iEmployee) 

对象雇员为:

public class Employee implements Serializable {

    private static final long serialVersionUID = -7315844547195801413L;

    private String employeeName;
    private Long employeeId;
    private @Valid @NotNull List<Address> addresses;

    // getter and setter methods

    @Validated
    public static class Address implements Serializable {

        private static final long serialVersionUID = 6748945632164495934L;

        private String addressId;

        @ValidAddress
        private String addressName;

        //getter and setter methods
    }
}

但是大张旗鼓将请求正文显示为:

{
 "addresses": {
   "addressId": "string",
   "addressName": "string",
   "permanentAddress": [
      {
        "addressId": "string",
        "addressName": "string"
      }
   ]
  },
 "employeeName": "string",
 "employeeId": 0
}

我的代码中没有对象永久地址。 该如何解决?

1 个答案:

答案 0 :(得分:0)

在质疑为什么要使用permantnAddress之前,我认为更重要的是找出为什么地址是addressId,addressName和Address列表的对象。 JSON中看起来不正确。

Employee对象看起来像:

{
  addresses: [
    addressId: "string",
    addressName: "string"
  ],
  employeeName: "string",
  employeeId: 0
}

permanentAddress是列表地址的正确对象

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