为什么login.php一直说密码无效?

时间:2019-02-21 16:14:55

标签: php mysql

所以,我有一个登录页面(login.php)

<?php
// Initialize the session
session_start();

// Check if the user is already logged in, if yes then redirect him to welcome page
if(isset($_SESSION["loggedin"]) && $_SESSION["loggedin"] === true){
  header("location: asdasd.php");
  exit;
}

// Include config file
require_once "config.php";

// Define variables and initialize with empty values
$username = $password = "";
$username_err = $password_err = "";

// Processing form data when form is submitted
if($_SERVER["REQUEST_METHOD"] == "POST"){

    // Check if username is empty
    if(empty(trim($_POST["username"]))){
        $username_err = "Please enter username.";
    } else{
        $username = trim($_POST["username"]);
    }

    // Check if password is empty
    if(empty(trim($_POST["password"]))){
        $password_err = "Please enter your password.";
    } else{
        $password = trim($_POST["password"]);
    }

    // Validate credentials
    if(empty($username_err) && empty($password_err)){
        // Prepare a select statement
        $sql = "SELECT id, felhasznalonev, jelszo FROM diakok WHERE felhasznalonev = ?";

        if($stmt = mysqli_prepare($link, $sql)){
            // Bind variables to the prepared statement as parameters
            mysqli_stmt_bind_param($stmt, "s", $param_username);

            // Set parameters
            $param_username = $username;

            // Attempt to execute the prepared statement
            if(mysqli_stmt_execute($stmt)){
                // Store result
                mysqli_stmt_store_result($stmt);

                // Check if username exists, if yes then verify password
                if(mysqli_stmt_num_rows($stmt) == 1){
                    // Bind result variables
                    mysqli_stmt_bind_result($stmt, $id, $username, $hashed_password);
                    if(mysqli_stmt_fetch($stmt)){
                        if(password_verify($password, $hashed_password)){
                            // Password is correct, so start a new session
                            session_start();

                            // Store data in session variables
                            $_SESSION["loggedin"] = true;
                            $_SESSION["id"] = $id;
                            $_SESSION["username"] = $username;

                            // Redirect user to welcome page
                            header("location: asdasd.php");
                        } else{
                            // Display an error message if password is not valid
                            $password_err = "The password you entered was not valid.";
                        }
                    }
                } else{
                    // Display an error message if username doesn't exist
                    $username_err = "No account found with that username.";
                }
            } else{
                echo "Oops! Something went wrong. Please try again later.";
            }
        }

        // Close statement
        mysqli_stmt_close($stmt);
    }

    // Close connection
    mysqli_close($link);
}
?>

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Login</title>
    <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.css">
    <style type="text/css">
        body{ font: 14px sans-serif; }
        .wrapper{ width: 350px; padding: 20px; }
    </style>
</head>
<body>
    <div class="wrapper">
        <h2>Login</h2>
        <p>Please fill in your credentials to login.</p>
        <form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">
            <div class="form-group <?php echo (!empty($username_err)) ? 'has-error' : ''; ?>">
                <label>Username</label>
                <input type="text" name="username" class="form-control" value="<?php echo $username; ?>">
                <span class="help-block"><?php echo $username_err; ?></span>
            </div>
            <div class="form-group <?php echo (!empty($password_err)) ? 'has-error' : ''; ?>">
                <label>Password</label>
                <input type="password" name="password" class="form-control">
                <span class="help-block"><?php echo $password_err; ?></span>
            </div>
            <div class="form-group">
                <input type="submit" class="btn btn-primary" value="Login">
            </div>
            <p>Don't have an account? <a href="register.php">Sign up now</a>.</p>
        </form>
    </div>
</body>
</html>

这样,我可以登录到由felvetel.php创建的帐户:

<?php
$teljes_nev = $_POST['teljes_nev'];
$kategoria = $_POST['kategoria'];
$felhasznalonev = $_POST['felhasznalonev'];
$idcske = "NULL";
header("Content-type: text/html; charset=utf-8");

if (!$teljes_nev) {
  echo "Kérem írja be a diák nevét.";
  exit;
}

if(!get_magic_quotes_gpc()) {
  $teljes_nev = addslashes($teljes_nev);
  $felhasznalonev = addslashes($felhasznalonev);
  $jelszo_alap = rand(1000,9999);
  $jelszo = password_hash($jelszo_alap, PASSWORD_DEFAULT);
}

@ $adatbazis = new mysqli('localhost', 'root', '', 'diakok');
$adatbazis->set_charset('utf8');
if (mysqli_connect_errno()) {
  echo "Nem sikerült csatlakozni az adatbázishoz. (1-es hibakód)";
}

$lekerdezes = "INSERT INTO diakok VALUES
              ('".$felhasznalonev."', '".$teljes_nev."', '".$jelszo."', '".$kategoria."', '".$idcske."', '".$idcske."' , '".$idcske."' ,'".$idcske."', '".$idcske."')";
$talalat = $adatbazis->query($lekerdezes);
if ($talalat) {
  echo $teljes_nev." nevű diák sikeresen felkerült az adatbázisba! (A diák jelszava ".$jelszo_alap.")";
} else {
  echo "Hiba! A diákot nem sikerült hozzáadni az adatbázishoz.";
}

$adatbazis->close();

?>

我的问题是它显示“您输入的密码无效”。同时输入正确的密码。 例如,我创建了一个名为admin.pelda的测试用户,其密码无password_hash()为2161。 现在,当我尝试登录该帐户时,它会向我提供无效的密码消息。 有什么想法可以解决吗? (我的config.php可以)

1 个答案:

答案 0 :(得分:0)

问题是散列密码确实很长,并且在数据库中,密码的最大长度设置为15。