使用递归找到所有可能的多米诺骨牌链

时间:2019-02-21 18:35:03

标签: c# recursion

我需要找到多米诺骨牌瓷砖的线性链的所有可能性。

示例:

Tiles : [3/4] [5/6] [1/4] [1/6]    
Possible chain : [3/4]-[4/1]-[1/6]-[6/5]

Here我找到了一个用Java语言编写的示例。我是新手,因此我需要帮助将Java代码转换为c#。我知道语言非常相似。

private static void listChains(List<Domino> chain, List<Domino> list)
{
    for (int i = 0; i < list.Count; ++i)
    {
        Domino dom = list[i];
        if (canAppend(dom, chain))
        {
            chain.Add(dom);
            Console.WriteLine(chain);
            Domino saved = list.RemoveAt(i);
            listChains(chain, list);
            list.Add(new Domino(i, saved));
            chain.Remove(chain.Count() - 1);
        }
        dom = dom.flipped();
        if (canAppend(dom, chain))
        {
            chain.Add(dom);
            Console.WriteLine(chain);
            Domino saved = list.RemoveAt(i);
            listChains(chain, list);
            list.Add(new Domino(i, saved));
            chain.RemoveAt(chain.Count() - 1);
        }
    }
}
  

严重性代码描述项目文件行抑制状态
  错误CS1503参数2:无法从'ConsoleApp2.Domino'转换为'int'23 Active
  错误CS0029无法将类型'void'隐式转换为'ConsoleApp2.Domino'21 Active
  错误CS1503参数1:无法从'int'转换为'ConsoleApp2.Domino'24 Active
  错误CS0029无法将类型'void'隐式转换为'ConsoleApp2.Domino'31 Active
  错误CS1503参数2:无法从'ConsoleApp2.Domino'转换为'int'33 Active
  错误CS1061'int'不包含'b'的定义,并且找不到可以接受的扩展方法'b'接受类型为'int'的第一个参数(您是否缺少using指令或程序集引用?)42 Active < br />

Domino saved = list.RemoveAt(i); list.Add(new Domino(i, saved));
chain.Remove(chain.Count() - 1); Domino saved = list.RemoveAt(i);
list.Add(new Domino(i, saved));

我不确定此方法的作用:(以及如何转换为c#)

private static boolean canAppend(Domino dom, List<Domino> to) {
    return to.isEmpty() || to.get(to.size()-1).b == dom.a;
}

1 个答案:

答案 0 :(得分:0)

以下是您发布的代码转换的截图:

public class Domino
{
    public int A { get; set; }
    public int B { get; set; }

    public Domino(int a, int b)
    {
        A = a;
        B = b;
    }

    public Domino Flipped()
    {
        return new Domino(B, A);
    }

    public override string ToString()
    {
        return $"[{A}/{B}]";
    }
}   

public class Program
{
    private static void ListChains(List<Domino> chain, List<Domino> list)
    {
        for (int i = 0; i < list.Count; ++i)
        {
            Domino dom = list[i];

            if (CanAppend(dom, chain))
            {
                chain.Add(dom);
                Console.WriteLine(string.Join("-", chain));
                Domino saved = list[i];
                list.RemoveAt(i);
                ListChains(chain, list);
                list.Insert(i, saved);
                chain.RemoveAt(chain.Count - 1);
            }

            dom = dom.Flipped();

            if (CanAppend(dom, chain))
            {
                chain.Add(dom);
                Console.WriteLine(string.Join("-", chain));
                Domino saved = list[i];
                list.RemoveAt(i);
                ListChains(chain, list);
                list.Insert(i, saved);
                chain.RemoveAt(chain.Count - 1);
            }
        }
    }

    private static bool CanAppend(Domino domino, List<Domino> chain)
    {
        return chain == null || chain.Count == 0 || chain.Last().B == domino?.A;
    }

    private static void Main()
    {
        var dominos = new List<Domino>
        {
            new Domino(3, 4),
            new Domino(5, 6),
            new Domino(1, 4),
            new Domino(1, 6)
        };

        ListChains(new List<Domino>(), dominos);

        Console.ReadKey();
    }
}

输出

![![enter image description here

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