以下查询是迄今为止我所能学习的最复杂的查询。它从tbl_user_time_log计算登录持续时间。
SELECT USER_ID,
UTL_DTSTAMP,
UTL_TASK,
SUM(UTL_DURATION) AS UTL_DURATION_TOTAL
FROM (
SELECT A.PK_USER_TIME_LOG_ID,
A.CLIENT_ID,
A.PROJECT_ID,
A.USER_ID,
A.UTL_DTSTAMP,
/* DATE_FORMAT(A.UTL_DTSTAMP,'%H:%i:%s') AS UTL_DTSTAMP, */
A.UTL_LATITUDE,
A.UTL_LONGITUDE,
A.UTL_EVENT,
A.UTL_TASK,
/* DURATION in seconds */
TIMESTAMPDIFF(SECOND, A.UTL_DTSTAMP, B.UTL_DTSTAMP) AS UTL_DURATION
FROM tbl_user_time_log A
INNER JOIN tbl_user_time_log B
ON B.PK_USER_TIME_LOG_ID = ( A.PK_USER_TIME_LOG_ID + 1 )
WHERE A.USER_ID = '465615'
/* Between current pay period Start date and Current pay period end date */
/* First day of the week is Monday.*/
AND ( A.UTL_DTSTAMP BETWEEN '2019-02-24' AND '2019-03-04' )
/* Filter out Clock Out. */
AND A.UTL_EVENT <> 'CLOCK OUT'
/* Our derived table... */
) AS tbl_derived_1
GROUP BY USER_ID, UTL_TASK;
...返回:
如何使用相同的查询,但是对于它选择的每个用户ID ,显示 tbl_user 中的相应的用户名和用户姓氏 >?
tbl_user
答案 0 :(得分:3)
假设您有一个表用户,该表用户的名字和姓氏由id关联到tbl_user_time_log 您可以使用联接
SELECT USER_ID,
u.firstname,
u.lastname,
UTL_DTSTAMP,
UTL_TASK,
SUM(UTL_DURATION) AS UTL_DURATION_TOTAL
FROM (
SELECT A.PK_USER_TIME_LOG_ID,
A.CLIENT_ID,
A.PROJECT_ID,
A.USER_ID,
A.UTL_DTSTAMP,
/* DATE_FORMAT(A.UTL_DTSTAMP,'%H:%i:%s') AS UTL_DTSTAMP, */
A.UTL_LATITUDE,
A.UTL_LONGITUDE,
A.UTL_EVENT,
A.UTL_TASK,
/* DURATION in seconds */
TIMESTAMPDIFF(SECOND, A.UTL_DTSTAMP, B.UTL_DTSTAMP) AS UTL_DURATION
FROM tbl_user_time_log A
INNER JOIN tbl_user_time_log B
ON B.PK_USER_TIME_LOG_ID = ( A.PK_USER_TIME_LOG_ID + 1 )
WHERE A.USER_ID = '465615'
/* Between current pay period Start date and Current pay period end date */
/* First day of the week is Monday.*/
AND ( A.UTL_DTSTAMP BETWEEN '2019-02-24' AND '2019-03-04' )
/* Filter out Clock Out. */
AND A.UTL_EVENT <> 'CLOCK OUT'
/* Our derived table... */
) AS tbl_derived_1
INNER JOIN user u ON u.id = tbl_derived_1.USER_ID
GROUP BY USER_ID, UTL_TASK;