Question

#include <stdio.h>
#include <string>

int main(){
    float a,b,z,u,r,k;
    char f,q,m;
    system("color B");
repeat:
    printf("Unesite broj a:  ");
    scanf("%f",&a);
repeatm:
    printf("Unesite broj b:  ");
    scanf("%f",&b);
    printf("Unesite funkciju (+,-,*,/):  ");
finput:
    scanf("%s",&f);
    if(f=='+'){
        goto zbroj;  
       }else{
        if(f=='-'){
            goto razlika;
        }else{
            if(f=='*'){
                goto umnozak;
            }else{
                if(f=='/'){
                    goto kolicnik;
                }else{
                    goto _newf;
                }
            }
        }
    }
//input of numbers and a check if the value of 'f' is one of the characters +,-,* or /
zbroj:
    z=a+b;
    printf("-------------------------------------\n");
    printf("Zbroj ta dva broja je: ");
    printf("%f \n",z);
    goto _new;
razlika:
    r=a-b;
    printf("-------------------------------------\n");
    printf("Razlika ta dva broja je: ");
    printf("%f \n",r);
    goto _new;
umnozak:
    u=a*b;
    printf("-------------------------------------\n");
    printf("Umnozak ta dva broja je: ");
    printf("%f \n",u);
    goto _new;
kolicnik:
   if(b==0){
        system("cls");
        printf("Ne mozete dijeliti s nulom \n");
        goto repeatB;
    }else{
 k=a/b;
    printf("-------------------------------------\n");
    printf("Kolicnik ta dva broja je: ");
    printf("%f \n",k);
    goto _new;
    }
//prints results
_newf:
    printf("Nevazeca funkcija, upisite ponovo:  ");
    goto finput;
//loop if 'f' isnt one of +,-,*,/
_new:
    printf("-------------------------------------\n");
    printf("Novi racun?(y/n)  ");
    scanf("%s",&q);
    system("cls");
    goto repeat1;
//asks if i want to exit or go back to start
repeat1:
    if(q=='y'){
        system("cls");
        goto memory;
    }else{
        if(q=='n'){
            goto exit;
        }else{
            printf("Novi racun? \n");
            printf("Molimo upisite y ili n:  ");
            scanf("%s", &q);
            goto repeat1;
        }
    }
//loops back to start
memory:
    printf("Zelite li iskoristits peredhodni rezultat kao broj a?(y/n):  ");
    scanf("%s", &m);
//asks if i want the previous result as the number 'a'
repeat2:
    if(m=='y'){
        system("cls");
        goto printfa;
    }else{
        if(m=='n'){
            system("cls");
            goto repeat;
        }else{
            printf("Zelite li iskoristits peredhodni rezultat kao broj a? \n");
            printf("Molimo upisite y ili n:  ");
            scanf("%s", &m);
            goto repeat2;
        }
    }
//checks if variable 'm' is either y or n
printfa:
    if(f=='+'){
        a=z;     
    }else{
        if(f=='-'){
            a=r;
        }else{
            if(f=='*'){
                a=u;
            }else{
                if(f=='/'){
                    a=k;       
                }
            }
        }
    }
//this should(?) overwrite the variable 'a'
//why isnt 'a' overwritten with the value of 'z', 'r', 'u' or 'k' here?
    printf("Broj a je:  %f \n", a); 
//here the value of 'a' stays the same as it was before
    goto repeatm;
repeatB:
    printf("Unesite broj b:  ");
    scanf("%f",&b);
    goto kolicnik;
exit:
    system("cls");
    system("pause");
    return(0);
}

有什么方法可以用值“ z”，“ r”，“ u”或“ k”之一覆盖变量“ a”（无手动输入）。该代码的结果只是一个+（或-，*，/）新b（我再次手动输入，但变量a与第一个输入相同）。请不要介意外语，它只是说“输入a”，“输入b”，“结果是..”，如果代码凌乱也很抱歉。

Answer 1

我只能间接地回答问题，因为直到我对代码稍加整理之后才开始研究实际的问题-但现在我没有得到错误。因此，答案是：清理代码，它可能会按预期工作。

我一直将结果保存在不同的变量中，尽管程序中现在不需要有多个HKCR:\\* HKCR:\`* 'HKCR:\*'变量。该程序的主要流程应与您的原始流程相似，但现在阅读起来有点容易：

result

有没有办法覆盖下面的代码中的变量

1 个答案: