通过使用WHERE中SELECT的值将两个SELECT查询组合在一起

Question

from Crypto.PublicKey import RSA
from Crypto.Signature import PKCS1_v1_5
from Crypto.Hash import SHA256
import base64

# This should be your Keygen account's public key
PUBLIC_KEY = \
"""-----BEGIN PUBLIC KEY-----
MIIBIjANBgkqhkiG9w0BAQEFAAOCAQ8AMIIBCgKCAQEAtmwlw+mDo2ZVBlRXa7Em
cj7cVrlwnwrIPC+Ij5KpltadJfwvRFvCr37USJvkc+FIND2dKk2mmbY32cvtxl3F
YLpjRwwlFuajbP8ZEdJl1YJyJDnLlKHWEfTSvTzZhpT939yjuBKoZ9A+wiIQ9tzY
F/ytb9zwPkOF7/XmPAaukah5xRgwsb3fo7E0CsBQuHZxFX83+nfdZ/60MWpSCWL6
AjNWDEmoLFEHVRm69+lwXTW51wojfurZy/wUw42sciHLV5A8mz7gJJGO5y+sGzzD
M5VxtmLz51Fl1Rl3fMzUAjPK77i9UDWo11EuNPrzMAgjmuuMLfpIDMlMR3n/ZsW7
XwIDAQAB
-----END PUBLIC KEY-----"""

# This should be the license key that you're cryptographically verifying
LICENSE_KEY = \
"""c29tZXJhbmRvbWtleQ==.oMTrvIz3IX4kre5UTzvkzCn712wulPvl9knSYBduYcGsX2W703zWMC9ZVepDytxLdpUIiCUtx6wx5OzmLx3rTzgaKqptrbf2wYHrCIPBgrhcHdJ3fLJRh8ASC_NdLK6i1jC_bEAq84d7QNLlTPC20aCmNLdxEJFy-DValGG0iFdxx6n6-Vp5oL8jSyWubAvBSqEQ4ubptcYirxpbDdC4DRpNzBuA48DGxWg6Pxq5HdGZWKS05iohNlrFkW-K8NJYHuLKszT0FN5UWcghx1oklagCm72aDvXm3CzKL2id7yL78X_V69JYsExx3fjRsU0pUe-f5lzKLB_HLTAdc0e1gQ=="""

# Split license key to obtain key and signature, then decode urlbase64 encoded values
enc_key, enc_sig = LICENSE_KEY.split(".")
key = base64.urlsafe_b64decode(enc_key)
sig = base64.urlsafe_b64decode(enc_sig)

# Verify the key's signature
pub_key = RSA.importKey(PUBLIC_KEY)
verifier = PKCS1_v1_5.new(pub_key)
digest = SHA256.new(data=key)

print(
  verifier.verify(digest, sig)
)

这就是我要在一个查询中执行的操作。如何将这两个查询结合在一起？

id | number
---|--------
1  | null
2  | 1
3  | null
4  | 0
5  | 4
6  | 4

第二次查询：

$id = 4;
SELECT * FROM users WHERE id = $id OR number = $id

// This will return rows 4,5,6

$id = 5; SELECT * FROM users WHERE id = $id AND id = $numberColumnOfId AND number = $numberOfColumnId; // This will return rows 4,5,6 是$numberColumnOfId中的number。因此，如果$id，则$id = 5为4。因此，选择ID = 5的行。

如何将两个SELECT语句组合在一起？

Answer 1

使用两个与UNION组合的查询。

第一个查询获取具有给定的$ id , the second query gets the ones that match via the number`列的行。

SELECT *
FROM users
WHERE id = $id OR number = $id
UNION
SELECT u1.*
FROM users AS u1
JOIN users AS u2 ON u1.number = u2.number OR u1.id = u2.number
WHERE u2.id = $id or u2.number = $id

DEMO