现在,我要做的就是将光标中的值打印在另一个下方。 最后一行被打印两次。
IF c_rules_present %ISOPEN THEN
CLOSE c_rules_present ;
END IF;
OPEN c_rules_present;
LOOP
FETCH c_rules_present INTO rule_present_record;
dbms_output.put_line(rule_present_record.rdr_dcd_cndtn);
EXIT WHEN c_rules_present %notfound;
END LOOP;
CLOSE c_rules_present;
POST /oauth/v2/accessToken HTTP/1.1
Host: www.linkedin.com
Content-Type: application/x-www-form-urlencoded
grant_type=authorization_code&code=987654321&redirect_uri=https%3A%2F%2Fwww.myapp.com%2Fauth%2Flinkedin&client_id=123456789&client_secret=shhdonottell
curl -X POST --header 'Content-Type: application/x-www-form-urlencoded' -d'{"grant_type":"authorization_code","code":"AQQaI-n6TkOm9po8-a28SQ9g-rEpWE-tjTJvat-DSKhulhpgB_1j93xFpO2y9wQGnu27z7WGJ57Fi1-AbdpGGEgL00Ay0lLHJgKNggYcxGGgTRkKsaEhyDIvDtVgyIf18eanRBPe5YYMFJKXM1Ojoygdgghkhrvx4wLORRkU-eDsZnhfUi7NltX_jKzrYQ","redirect_uri":"http://localhost:3000","client_id":"81k22s8wipax2r","client_secret":"dm2rcFp1631BSMDe"}' 'www.linkedin.com/oauth/v2/accessToken HTTP/1.1'
答案 0 :(得分:3)
只需将EXIT WHEN
条件向上移动:
IF c_rules_present %ISOPEN THEN
CLOSE c_rules_present ;
END IF;
OPEN c_rules_present;
LOOP
FETCH c_rules_present INTO rule_present_record;
EXIT WHEN c_rules_present %notfound;
dbms_output.put_line(rule_present_record.rdr_dcd_cndtn);
END LOOP;
CLOSE c_rules_present;