Question

任何人在线。我需要帮助。我有一个像这样的数组。

var array = [ {
roomNumber: 'R01',
roomType: 'Deluxe',
basic_facilities: 'Hot Water',
additional_facilities: 'Iron' },
    {
roomNumber: 'R01',
roomType: 'Deluxe',
basic_facilities: 'Minibar',
additional_facilities: 'AC' },
    {
roomNumber: 'R01',
roomType: 'Deluxe',
basic_facilities: 'cold Water',
additional_facilities: 'Fan' },
    {
roomNumber: 'R02',
roomType: 'standerd',
basic_facilities: 'View',
additional_facilities: 'Washing' },
         {
roomNumber: 'R02',
roomType: 'standerd',
basic_facilities: 'View 2',
additional_facilities: 'wash' }
    ]

我想像这样

var result =[{
roomNumber: 'R01',
roomType: 'Deluxe',
basic_facilities: ['Hot Water','Minibar','cold Water'],
additional_facilities: ['Iron','AC','fan'] },{
roomNumber: 'R02',
roomType: 'standerd',
basic_facilities: ['View','View 2'],
additional_facilities: ['Washing','wash'] }]

我知道这是一个基本的东西。但是我需要一个帮助。谢谢。

这是我到目前为止所做的。

 var array = [ {
roomNumber: 'R01',
roomType: 'Deluxe',
basic_facilities: 'Hot Water',
additional_facilities: 'Iron' },
    {
roomNumber: 'R01',
roomType: 'Deluxe',
basic_facilities: 'Minibar',
additional_facilities: 'AC' },
    {
roomNumber: 'R01',
roomType: 'Deluxe',
basic_facilities: 'cold Water',
additional_facilities: 'Fan' },
    {
roomNumber: 'R02',
roomType: 'standerd',
basic_facilities: 'View',
additional_facilities: 'Washing' },
         {
roomNumber: 'R02',
roomType: 'standerd',
basic_facilities: 'View 2',
additional_facilities: 'wash' }
    ]
    result = [];

array.forEach(function (a) {
    if (!this[a.roomNumber]) {
        this[a.roomNumber] = { roomNumber: a.roomNumber};
        result.push(this[a.roomNumber]);
    }
}, Object.create(null));

 console.log(result);

Answer 1

看起来您正在尝试在迭代时将各项组合到一个对象中，这是正确的主意，但是用于实现该目的的方法是reduce：回调的第一个参数是 last 迭代返回的值（或者，在第一次迭代中，初始值-传递给.reduce的第二个参数）。

在每次迭代中，如果尚未在累加器（第一个参数）上在roomNumber上创建对象，则将其推入basic_facilities和additional_facilities数组在那个对象中。最后，使用Object.values将对象转换为其值的数组：

var array = [{
    roomNumber: 'R01',
    roomType: 'Deluxe',
    basic_facilities: 'Hot Water',
    additional_facilities: 'Iron'
  },
  {
    roomNumber: 'R01',
    roomType: 'Deluxe',
    basic_facilities: 'Minibar',
    additional_facilities: 'AC'
  },
  {
    roomNumber: 'R01',
    roomType: 'Deluxe',
    basic_facilities: 'cold Water',
    additional_facilities: 'Fan'
  },
  {
    roomNumber: 'R02',
    roomType: 'standerd',
    basic_facilities: 'View',
    additional_facilities: 'Washing'
  },
  {
    roomNumber: 'R02',
    roomType: 'standerd',
    basic_facilities: 'View 2',
    additional_facilities: 'wash'
  }
];

const roomsByRoomNumber = array.reduce((a, item) => {
  const { roomNumber, roomType, basic_facilities, additional_facilities } = item;
  if (!a[roomNumber]) {
    a[roomNumber] = { roomNumber, roomType, basic_facilities: [], additional_facilities: [] };
  }
  a[roomNumber].basic_facilities.push(basic_facilities);
  a[roomNumber].additional_facilities.push(additional_facilities);
  return a;
}, {});
const result = Object.values(roomsByRoomNumber);
console.log(result);

Answer 2

似乎您想结合roomNumber,roomType的基础数组。您可以使用reduce()和findIndex()来实现。

var arr = [ {roomNumber: 'R01',roomType: 'Deluxe',basic_facilities: 'Hot Water',additional_facilities:'Iron' },
   {roomNumber: 'R01',roomType: 'Deluxe',basic_facilities: 'Minibar',additional_facilities: 'AC' },
    {roomNumber: 'R01',roomType: 'Deluxe',basic_facilities: 'cold Water',additional_facilities: 'Fan' },
    {roomNumber: 'R02',roomType: 'standerd',basic_facilities: 'View',additional_facilities: 'Washing' },
    {roomNumber: 'R02',roomType: 'standerd',basic_facilities: 'View 2',additional_facilities: 'wash' }
]

let mkeys = ['roomNumber','roomType']
let ckeys = ['basic_facilities','additional_facilities']
let result = arr.reduce((ac,a) => {
  let ind = ac.findIndex(x => mkeys.every(key => x[key] === a[key]));
  a = JSON.parse(JSON.stringify(a));
  ckeys.forEach(key => a[key] = [a[key]]);
  ind === -1 ? ac.push(a) : ckeys.forEach(key => ac[ind][key].push(a[key][0]));
  return ac;
},[])
console.log(result);

如果内部对象相同，则为javascript合并数组

2 个答案: