查询多个条件

Question

希望有人可以帮助我理解为什么第一个查询有效而第二个查询无效。 我的目标是首先显示状态为“关闭”的行，然后显示状态为“等待”的行

 "SELECT *  from job WHERE status='close' AND status='wait' ";

 "SELECT *  from job WHERE status='close ";

我尝试执行此操作，但是我想显示除“已删除”之外的所有状态

$sql = "SELECT id,date, device,model,problem,status,assigned  from job  ORDER BY FIELD(status,'deler_trenger','deler_bestilt','new','progress','wait','done','close','cancel')";

Answer 1

在status<>'deleted'处使用where条件

SELECT id,date, device,model,problem,status,assigned  from job  
where status<>'deleted'
ORDER BY FIELD(status,'deler_trenger','deler_bestilt','new','progress','wait','done','close','cancel')

Answer 2

'close后缺少单引号。另外，请尝试使用status!='deleted'或status<>'deleted'。