为酒店预订应用程序找到最佳的MongoDB结构和架构

时间:2019-03-15 12:41:25

标签: node.js database mongodb nosql

我正在构建酒店预订应用程序。制作一个非常简单的应用程序所需的信息是:一个旅馆,属于每个旅馆的房间以及属于每个房间的预订。

以嵌套为例,它看起来(忽略一些_id不是唯一的,这只是一个快速演示):

{"_id":"5c8639a856be210634dfcf16",
"hotelName":"Hotel A",
"hotelDescription":"The best hotel ever",

"rooms":{
         {"_id":"1235e56be210634dfcf13",
         "roomNumber":"1",
         "bookable: True",

         "reservations":{
                         {"_id":"5c86365e56be21a634dfasdf",
                         "from":"2019-01-01",
                         "to": "2019-01-06"},

                         {"_id":"5c86365e56be21a634dfasdf",
                         "from":"2019-01-06",
                         "to": "2019-01-10"},

                         {"_id":"123455e56be21a634dfasdf",
                         "from":"2019-01-15",
                         "to": "2019-01-20"},

                        }
         },


         {"_id":"1235e56be210634dfcf13",
         "roomNumber":"2",
         "bookable: True",

         "reservations":{
                         {"_id":"5c86365e56be21a634dfasdf",
                         "from":"2019-01-01",
                         "to": "2019-01-06"},

                         {"_id":"5c86365e56be21a634dfasdf",
                         "from":"2019-01-06",
                         "to": "2019-01-10"},

                         {"_id":"123455e56be21a634dfasdf",
                         "from":"2019-01-15",
                         "to": "2019-01-20"},

                        }
         }

}

如您所见,房间被嵌套在酒店中,预订被嵌套在房间中。这将永远不会更深。一个普通的酒店可以有400间客房,平均每年50个预订。

但是。我想知道我应该对此进行非规范化吗?

那么简单: (所有_id由Mongodb自动生成)

Hotels
    Hotel _id:1,
    Hotel _id:2,
    Hotel _id:3,

Rooms
    Hotel _id:1 
        Room _id:1,
        Room _id:2,
        Room _id:3,
    Hotel _id:2
        Room _id:4,
        Room _id:5,
        Room _id:6,

Reservations:
    Room _id:1
        Reservation _id:1,
        Reservation _id:2,
        Reservation _id:3,
    Room _id:2
        Reservation _id:4,
        Reservation _id:5,
        Reservation _id:6

1 个答案:

答案 0 :(得分:0)

以下架构可以帮助您实现要求,

/* 1 */
{
    "_id" : 1.0,
    "hotelname" : "hotel1",
    "rooms" : [ 
        {
            "roomno" : "room11",
            "reservations" : [ 
                {
                    "reservationid" : "reservation111",
                    "startDate" : "2019-03-18",
                    "endDate" : "2019-03-20"
                }, 
                {
                    "reservationid" : "reservation112",
                    "startDate" : "2019-03-21",
                    "endDate" : "2019-03-25"
                }
            ]
        }, 
        {
            "roomno" : "room12",
            "reservations" : [ 
                {
                    "reservationid" : "reservation121",
                    "startDate" : "2019-03-15",
                    "endDate" : "2019-03-18"
                }, 
                {
                    "reservationid" : "reservation122",
                    "startDate" : "2019-03-19",
                    "endDate" : "2019-03-21"
                }
            ]
        }
    ]
}

/* 2 */
{
    "_id" : 2.0,
    "hotelname" : "hotel2",
    "rooms" : [ 
        {
            "roomno" : "room21",
            "reservations" : [ 
                {
                    "reservationid" : "reservation211",
                    "startDate" : "2019-03-18",
                    "endDate" : "2019-03-20"
                }, 
                {
                    "reservationid" : "reservation212",
                    "startDate" : "2019-03-21",
                    "endDate" : "2019-03-25"
                }
            ]
        }, 
        {
            "roomno" : "room22",
            "reservations" : [ 
                {
                    "reservationid" : "reservation221",
                    "startDate" : "2019-03-15",
                    "endDate" : "2019-03-18"
                }, 
                {
                    "reservationid" : "reservation222",
                    "startDate" : "2019-03-19",
                    "endDate" : "2019-03-21"
                }
            ]
        }
    ]
}
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