x的冲突类型和先前的声明在这里......什么?

时间:2011-04-01 21:22:46

标签: c function void

当我有时间的时候,我一直在教自己C几个月,我遇到了一个问题,我不知道如何解决。

具体来说,当我尝试使用gcc编译它时,我得到:

geometry.c:8: error: conflicting types for ‘trapezoid’
geometry.c:7: note: previous declaration of ‘trapezoid’ was here
geometry.c:48: error: conflicting types for ‘trapezoid’
geometry.c:7: note: previous declaration of ‘trapezoid’ was here
geometry.c:119: error: conflicting types for ‘trapezoid_area’
geometry.c:59: note: previous implicit declaration of ‘trapezoid_area’ was here
geometry.c: In function ‘cone_volume’:
geometry.c:128: error: called object ‘3.14100000000000001421085471520200371742248535156e+0’ is not a function
geometry.c: In function ‘cylinder_volume’:
geometry.c:136: error: called object ‘3.14100000000000001421085471520200371742248535156e+0’ is not a function

现在,我想我可能需要对这些功能进行类型转换,但同样,我不确定。

看起来它想要读取我定义为3.141的PI作为函数。有没有办法可以避免使用魔法数字3.141(虽然它比其他数字少得多)?

//Geometric formulae
#include <stdio.h>
#include <math.h>

#define PI 3.141

float trapezoid(float b1, float b2, float h);
int trapezoid();
float sphere_volume(float r);
int sphere();
float cone_volume(float r, float h);
int cone();
float pyramid_volume(float b, float h);
int pyramid();
float cylinder_volume(float r, float h);
int cylinder();

int main(void) {
        char selection = 0;

        while(selection != 'q') {
                printf("\t--Geometric Formulas--\n");
                printf("\tSelection an option from the menu: ");
                scanf("%c", & selection);
                switch(selection) {
                        case 1: //Trapezoid area
                                printf("%d", trapezoid());
                                break;
                        case 2: //Sphere volume
                                printf("%d", sphere());
                                break;
                        case 3: //Cone volume
                                printf("%d", cone());
                                break;
                        case 4: //Pyramid volume
                                printf("%d", pyramid());
                                break;
                        case 5: //Cylinder volume
                                printf("%d", cylinder());
                                break;
                        default:
                                break;
                }
        }
}
//      --Shape Menus--
//Trapezoid
int trapezoid() {
        float h = 0, b1 = 0, b2 = 0;
        float traparea;

        printf("\tTrapezoid base 1: ");
        scanf("%3f", &b1);
        printf("\tTrapezoid base 2: ");
        scanf("%3f", &b2);
        printf("\tTrapezoid height: ");
        scanf("%3f", &b2);

        traparea = trapezoid_area(b1, b2, h);

        printf("\tTrapezoid Area: %3f\n", traparea); }

//Sphere
int sphere() {
        float r = 0;
        float spherevol;

        printf("\tSphere radius: ");
        scanf("%f", &r);

        spherevol = sphere_volume(r);

        printf("\tSphere volume: %3f\n", spherevol); }

//Cone
int cone() {
        float r = 0, h = 0;
        float conevol;

        printf("\tCone radius: ");
        scanf("%f", &r);
        printf("\tCone height: ");
        scanf("%f", &h);

        conevol = cone_volume(r, h);

        printf("\tCone volume: %3f\n", conevol); }

//Pyramid
int pyramid() {
        float b = 0, h = 0;
        float pyramidvol;

        printf("\tPyramid base: ");
        scanf("%f", &b);
        printf("\tPyramid height: ");
        scanf("%f", &h);

        pyramidvol = pyramid_volume(b, h);

        printf("\tPyramid volume: %3f\n", pyramidvol); }

//Cylinder
int cylinder() {
        float r = 0, h = 0;
        float cylindervol;

        printf("\tCylinder radius: ");
        scanf("%f", &r);
        printf("\tCylinder height: ");
        scanf("%f", &h);

        cylindervol = cylinder_volume(r, h);

        printf("Cylinder volume: %3f", cylindervol); }

//      --Geometric Formulas--
//Trapezoid Area Computation
float trapezoid_area(float b1, float b2, float h) {
        return ((b1 + b2) * h) / 2; }

//Sphere Volume Computation
float sphere_volume(float r) {
        return ((pow(r,3)) * (4 * PI)) / 3; }

//Cone Volume Computatioin
float cone_volume(float r, float h) {
        return ((PI(pow(r,2)) * h)) / 3; }

//Pyramid Volume Computation
float pyramid_volume(float b, float h) {
        return (b * h) / 3; }

//Cylinder Volume Computation
float cylinder_volume(float r, float h) {
        return (PI(pow(r,2))) * h; }

6 个答案:

答案 0 :(得分:7)

他们中的任何一个都说有一个“隐含的”定义:这可以通过预先声明来解决。例如,您预先声明了 float trapezoid int trapezoid ,但您没有预先声明 trapezoid_area 。正如其他人所指出的那样,你也不能像在C ++中那样在C中重载。

在一些领域,你试图进行隐式乘法 - 例如, PI(pow(r,2))应该 PI *(pow(r,2))

答案 1 :(得分:4)

您看到的错误是因为您使用不同的签名两次定义相同的功能

float trapezoid(float b1, float b2, float h);
int trapezoid();

根据您的其他定义,看起来第一个trapezoid函数应该命名为trapezoid_volume

float trapezoid_volume(float b1, float b2, float h);
int trapezoid();

答案 2 :(得分:3)

C 不支持函数重载。 C ++ 可以。

由于您不小心将trapezoid_volume声明为trapezoid,因此会出现编译错误。

答案 3 :(得分:1)

你定义了两次函数梯形。 C不是C ++。您不能像使用重载功能一样使用不同的签名定义相同的函数。

答案 4 :(得分:1)

#define PI 3.141

float trapezoid(float b1, float b2, float h);
int trapezoid();

我想你想要

float trapezoid_volume(...);
/*             ^^^^^^^                 */

答案 5 :(得分:0)

要回答关于定义PI的问题 - pi通常在math.h中定义(如M_PI),但由于它不是实际标准的一部分,您可能需要进行一些配置为拿到它,为实现它。

例如,在使用MSVC时,您需要定义_USE_MATH_DEFINES才能获得它。见

如果您的平台没有它,您可能希望将以下内容添加到标题中:

#ifndef
#define M_PI 3.14159265358979323846264338327
#endif
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