Question

I am looking to compare package versions in ruby. Some of my package names are develop-SNAPSHOT.

When using something like

Gem::Version.new('develop-SNAPSHOT-1529333073') > Gem::Version.new('develop-SNAPSHOT')

I get the response

ArgumentError: Malformed version number string develop-SNAPSHOT-1529333073

In python I would use packaging.version.parse() to compare similar strings to this and it would work fine with that, is there anything equivalent in Ruby?

Answer 1

根据doc：

版本字符串通常应该是一系列由句点分隔的数字。每个部分（用句点分隔的数字）被认为是自己的编号，这些用于排序。例如，3.10比3.2高，因为十大于二。

因此，您的版本字符串（'develop-SNAPSHOT-1529333073'和'develop-SNAPSHOT'）的格式均错误。

您应该更改版本字符串的格式，例如到'1529333073'而没有前缀，一切都会好的。

如果要在版本字符串中包含前缀，则需要在使用Gem::Version.new()之前将其删除。
例如，下面的代码将按预期工作：

Gem::Version.new('develop-SNAPSHOT-1529333073'.sub(/develop-SNAPSHOT-?/, '')) > 
   Gem::Version.new('develop-SNAPSHOT'.sub(/develop-SNAPSHOT-?/, ''))

=> true

Comparing versions in Ruby with develop-SNAPSHOT

1 个答案: