Question

我尝试在groovy脚本中实现curl命令。目标是确定Asana中的任务。该命令在命令提示符中可以正常运行，但是当我尝试在groovy脚本中运行它时失败。这是我的命令：

curl -v -H "Authorization: Bearer <myToken>" https://app.asana.com/api/1.0/tasks --data-urlencode "projects=<projectId>" --data-urlencode "notes=message" --data-urlencode "name=null"

我得到的错误是：

{"errors":[{"message":"Could not interpret \"projects as an identifier in \"projects.","help":"For more information on API status codes and how to handle them, read the docs on errors: https://asana.com/developers/documentation/getting-started/errors"}]}

我还尝试将命令放入列表中，但是curl尝试将列表的每个部分作为主机解析：

def command = ["curl",
           "https://app.asana.com/api/1.0/tasks",
           "-H","Authorization:","${authorizationToken}",
           "--data-urlencode","projects=","${projects}",
           "--data-urlencode","notes=","${notes}",
           "--data-urlencode","name=","${name}"];

如何在groovy脚本中正确转义data-urlencode参数？这与groovy运行时有关吗，因为groovy试图不断重建URL？

“无法将\“项目解释为\”项目“中的标识符。

0 个答案: