Question

执行以下操作的最有效方法是什么？

A = ["A","B","C"]
B = [range(19,21)]

列表结果：

C = ["A19", "B19", "C19", "A20", "B20", "C20"]

非常感谢！

Answer 1

itertools.product也可以使用：

from itertools import product

A = ["A","B","C"]
C = [a + str(n) for n, a in product(range(19, 21), A)]

请注意，有多种方法可以将字符串（a）和数字n格式化为单个字符串：

a + str(n)
"{}{}".format(a, n)
f"{a}{n}"  # for python >= 3.6

Answer 2

使用列表理解：

A = ["A","B","C"]
B = range(19,21)
print([x+str(y) for y in B for x in A])

或者版本高于Python 3.6：

print([f"{x}{y}" for y in B for x in A])

输出：

['A19', 'B19', 'C19', 'A20', 'B20', 'C20']

编辑：

使用此：

A = ["X","Y","Z"]
B = range(19,21)
C = [x+str(y) for y in B for x in A]
print(C)
curveexpression = ""
for zoo in "Animal":
    for month in C:
        arrival += "[%s,%s];" % (zoo, month)
print(arrival)

Answer 3

您可以使用以下listcomp：

from itertools import product

A = ["A","B","C"]
B = range(19,21)

[i + j for i, j in product(A, map(str, B))]
# ['A19', 'A20', 'B19', 'B20', 'C19', 'C20']

或

from itertools import product
from operator import concat

[concat(*i) for i in product(A, map(str, B))]
# ['A19', 'A20', 'B19', 'B20', 'C19', 'C20']

如果要从某个范围构建列表，请使用函数list()：

list(range(19, 21))
# [19, 20]

Answer 4

对于列表中的范围：

B = [*range(19, 21)]:

C = [a + str(b) for b in B for a in A]

循环并合并以创建新列表

4 个答案: