Question

我正在检索叶子的路径，并且嵌套集中有重复的叶子名称。执行查询后，将重复叶名的不同路径合并在一起。

我试图修复sql代码，但无法达到预期的结果

foreach($leafs as $id=>$leaf) {
            $sql_fetch = 'SELECT parent.name, node.category_id '
                . 'FROM vender_category AS node, '
                . 'vender_category AS parent '
                .'WHERE (node.lft BETWEEN parent.lft AND parent.rgt) '
                .'AND node.name = "'.$leaf['name'].'" '
                .'ORDER BY parent.lft ';

            $venderCategories[] = Yii::app()->db->createCommand($sql_fetch)->queryAll();
        }
$categoryChains = array();
        foreach ($venderCategories as $key => $venderCategory) {
                $categoryChains[] = array(
                    'name' => implode(' / ', array_column($venderCategory, 'name')),
                    'category_id' => implode(array_unique( array_column($venderCategory, 'category_id'))),
                );
        }

此代码将具有相同名称的Leaf路径合并在一起

array ( 'name' => 'smartphone / accessories / car / accessories' );

我想要2个同名'accessories'的叶子像这样分开：

array ( 'name' => 'smartphone / accessories );

array ( 'name' => 'car / accessories' );

谢谢！

Answer 1

实际上这很容易，但是由于我是编程新手，所以对我来说很难：）

这是我的解决方法。只需添加一个条件即可查询。

 $sql_fetch = 'SELECT parent.name, node.category_id '
                . 'FROM vender_category AS node, '
                . 'vender_category AS parent '
                .'WHERE (node.lft BETWEEN parent.lft AND parent.rgt) '
                .'AND node.name = "'.$leaf['name'].'" '
                **.'AND node.category_id = "'.$leaf['category_id']. '" '**
                .'ORDER BY parent.lft ';

在嵌套集中重复节点名称

1 个答案: