Question

我有两个表' User '和' Address '，它们之间存在 OneToOne 关系，因为 User表有一个列“ address_id”，用于存储地址表的“ id” 。

这是用户实体中的注释：

/**
     * @ORM\OneToOne(targetEntity="App\Entity\address", cascade={"persist", "remove"})
     * @ORM\JoinColumn(nullable=false)
     */
    private $address;

Security.yaml：

security:
    encoders:
        App\Entity\User:
            algorithm: bcrypt

    providers:
        my_provider:
            entity:
                class: App\Entity\User
                property: username
    firewalls:
        dev:
            pattern: ^/(_(profiler|wdt)|css|images|js)/
            security: false
        main:
            anonymous: true

            form_login:
                login_path: login
                check_path: login
                provider: my_provider
                default_target_path: dashboard

            logout:
                path: /logout
                target: /

    access_control:
        - { path: ^/login, roles: IS_AUTHENTICATED_ANONYMOUSLY  }
        - { path: ^/dashboard, roles: ROLE_USER }

控制器：

namespace App\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\AbstractController;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\Routing\Annotation\Route;
use Symfony\Component\Security\Http\Authentication\AuthenticationUtils;

class SecurityController extends AbstractController
{
    /**
     * @Route("/login", name="login")
     */
    public function login(Request $request,AuthenticationUtils $utils)
    {
        // get the login error if there is one
        $error = $utils->getLastAuthenticationError();
        // dump($error);die;

        // last username entered by the user
        $lastUsername = $utils->getLastUsername();
        return $this->render('security/login.html.twig', [
            'last_username' => $lastUsername,
            'error' => $error
            ]);
    }

    public function logout()
    {
        # code...
    }   
}

插入用户名和密码时出现此错误：

由于系统问题，无法处理身份验证请求。

这是我在控制器中转储错误时得到的。

SecurityController.php on line 20:
AuthenticationServiceException {#189 ▼
  -token: UsernamePasswordToken {#236 ▶}
  #message: "The target-entity App\Entity\address cannot be found in 'App\Entity\User#address'."
  #code: 0
  #file: "/home/users/kumar.saurabh/www/html/symfony/test-project/vendor/symfony/security-core/Authentication/Provider/DaoAuthenticationProvider.php"
  #line: 85
  trace: {▶}
}

当我删除$ address变量及其getter和setter函数时，登录工作正常，但是当我使用它时，会出现上述错误。

如何使用外键来实现这一目标？我是symfony的新手，并且正在学习4.2版。

Answer 1

请注意情况，将App \ Entity \ address替换为App \ Entity \ Address，更新您的架构，这应该没问题

/**
 * @ORM\OneToOne(targetEntity="App\Entity\address", cascade={"persist", "remove"})
 * @ORM\JoinColumn(nullable=false)
 */
private $address;

应该是

/**
 * @ORM\OneToOne(targetEntity="App\Entity\Address", cascade={"persist", "remove"})
 * @ORM\JoinColumn(nullable=false)
 */
private $address;

由于两个表之间的外键约束，无法登录

1 个答案: