如何将mongodb $ lookup与嵌套数组一起使用?

时间:2019-03-26 15:55:16

标签: mongodb aggregation-framework

我正在尝试执行将两个集合组合在一起的搜索查询。

集合1称为股票集合。

{ "fruit_id" : "1", "name" : "apples", "stock": 100 }
{ "fruit_id" : "2", "name" : "oranges", "stock": 50 }
{ "fruit_id" : "3", "name" : "plums", "stock": 60 } 

集合2称为订单集合

{ "order_id" : "001", "ordered_fruits":
    [
     {"fruit_id" : "1", "name" : "apples", "ordered" : 5},
     {"fruit_id" : "3", "name" : "plums", "ordered" : 20}
    ]
}
{ "order_id" : "002", "ordered_fruits":
    [
     {"fruit_id" : "2", "name" : "oranges", "ordered" : 30},
     {"fruit_id" : "3", "name" : "plums", "ordered" : 20}
    ]
}

我正在尝试编写一个查询,该查询返回带有附加键对的 stock 集合,该键对代表订购的水果总量。

{ "fruit_id" : "1", "name" : "apples", "stock": 100, "ordered": 5 }
{ "fruit_id" : "2", "name" : "oranges", "stock": 50, "ordered": 30 }
{ "fruit_id" : "3", "name" : "plums", "stock": 60, "ordered": 40 }

我尝试从聚合框架中使用 $ lookup ,但嵌套数组使它变得复杂。我现在很困。

1 个答案:

答案 0 :(得分:2)

您可以使用以下汇总

db.stock.aggregate([
  { "$lookup": {
    "from": "orders",
    "let": { "fruitId": "$fruit_id" },
    "pipeline": [
      { "$match": { "$expr": { "$in": ["$$fruitId", "$ordered_fruits.fruit_id"] }}},
      { "$unwind": "$ordered_fruits" },
      { "$match": { "$expr": { "$eq": ["$ordered_fruits.fruit_id", "$$fruitId"] }}}
    ],
    "as": "orders"
  }},
  { "$project": {
    "ordered": { "$sum": "$orders.ordered_fruits.ordered" },
    "fruit_id" : 1, "name" : 1, "stock": 1
  }}
])

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