如何将类似数组的字符串转换为数组

Question

我有一个具有以下值的字符串：“” OneV“，” TwoV“，” ThreeV“”

我想知道是否有办法将这个字符串转换成具有以下值的数组：[“ OneV”，“ TwoV”，“ ThreeV”]

Answer 1

尝试一下：

let aString = " \"OneV\", \"TwoV\", \"ThreeV\" "  
let newString = aString.replacingOccurrences(of: "\"", with: "")
let stringArr = newString.components(separatedBy: ",")
print(stringArr)

如果字符串在字符串中不包含"，则

let aString = "OneV,TwoV,ThreeV"  
let stringArr = aString.components(separatedBy: ",")
print(stringArr)

Answer 2

迅速

let str = "\"OneV\", \"TwoV\", \"ThreeV\""
let ary = str.components(separatedBy: ",")

Answer 3

要将字符串拆分为数组，可以使用

string.split(separator: ",")

这会将字符串从“ 1,2,3,4,5”转换为[“ 1”，“ 2”，“ 3”，“ 4”，“ 5”]

Answer 4

您可以使用两个指针遍历字符串，并在两个双引号（或您选择的任意字符）之间的之间寻找字符：

func substrings(of str: String, between char: Character) -> [String] {
    var array = [String]()

    var i = str.startIndex

    while i < str.endIndex {
        while i < str.endIndex, str[i] != char {
            i = str.index(after: i)
        }

        if i == str.endIndex { break }

        i = str.index(after: i)

        var j = i

        while j < str.endIndex, str[j] != char { 
            j = str.index(after: j) 
        }

        guard j < str.endIndex else { break }

        if j > i { array.append(String(str[i..<j])) }

        i = str.index(after: j)
    }

    return array
}

这是一些用例：

let s1 = "\"OneV\", \"TwoV\", \"ThreeV\""
substrings(of: s1, between: "\"") //["OneV", "TwoV", "ThreeV"]

let s2 = "\"OneV\", \"TwoV\", \"Thr"
substrings(of: s2, between: "\"") //["OneV", "TwoV"]

let s3 = "|OneV|, |TwoV|, |ThreeV|"
substrings(of: s3, between: "|") //["OneV", "TwoV", "ThreeV"]

let s4 = "abcdefg"
substrings(of: s4, between: ",") //[]