我确实有开店，但是当我要打印关店时，查询将开店打印为关店。我的目标是进行相同的查询以打印开店和关店，因为现在我有两个不同的查询。
对我来说困难的是，餐厅每天可能营业两次。例如，餐厅，开放时间为星期一的上午10点至星期二03上午，星期二的上午10点至星期三03上午。
我尝试进行CASE WHEN查询，但问题是它无法获得带有打印状态的餐厅ID。
我的有两个插入餐厅的营业时间表注意，餐厅ID是餐厅表的外键。
id,restaurantID,openday,opentime,closeday,closetime
1,15,Monday,10:00:00,Tuesday,03:00:00
2,15,Tuesday,10:00:00,Wednesday,03:00:00
3,24,Monday,10:00:00,Tuesday,03:00:00
4,24,Tuesday,10:00:00,Wednesday,03:00:00
5,24,Wednesday,10:00:00,Thursday,04:00:00
6,24,Thursday,10:00:00,Friday,02:00:00
7,24,Friday,10:00:00,Saturday,01:00:00
8,24,Saturday,11:00:00,Sunday,01:00:00
9,24,Sunday,11:00:00,Monday,02:00:00
下面的第一个查询可完美打印开餐厅。 我如何获得封闭的餐厅？
查询开放餐厅的查询
$stmt = $pdo->prepare("SELECT * FROM
business_hour
INNER JOIN restaurant
ON business_hour.restaurantID =
restaurant.id
WHERE
(closeday = '$today' AND closetime >=
'$timeNow')
OR
(openday = '$today' AND opentime <=
'$timeNow')
");
$stmt->execute();
$i=0;
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
echo $row['ravintolaID'].' '.'OPEN'.' '.$row['openday'].' '.$row['opentime'].' --'.$row['closeday'].' '.$row['closetime'].' '.'<br>';
$i++;
}
用于检查已关闭餐厅的查询
$stmt = $pdo->prepare("SELECT * FROM business_hour
INNER JOIN restaurant
ON business_hour.restaurantID = restaurant.id
WHERE
(closeday = '$today' AND closetime < '$timeNow')
OR
(openday = '$today' AND opentime > '$timeNow')
");
$stmt->execute();
$i=0;
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
echo $row['ravintolaID'].' '.'CLOSED'.' open at '.$row['openday'].' '.$row['opentime'].' -- '.$row['closeday'].' '.$row['closetime'].' '.'<br>';
$i++;
}
我希望输出显示我只有一次关闭和打开餐厅。
当前日期为星期一，时间为 7am
24 OPEN Sunday 10:00:00 --Monday 08:00:00
15 CLOSED open at Monday 10:00:00 -- Tuesday 03:00:00
15 CLOSED open at Sunday 10:00:00 -- Monday 03:00:00
24 CLOSED open at Monday 10:00:00 -- Tuesday 03:00:00