如何从PHP中的关联数组构建多维数组树?

时间:2019-03-30 20:08:48

标签: php arrays multidimensional-array tree

我正在尝试通过将“ s”和“ d”键字符串值替换为其各自的键“ bandnumber”数组来从关联数组构建多维数组树,但似乎无法破解它。我只能使它适用于数组的第一个节点。

例如,我有以下数组:

$coiArray = array (
    array('bandnumber' => '02-BELG-2129929', 's'  =>'94-BELG-3237180', 'd' => '96-BELG-3156295' ),
    array('bandnumber' => '94-BELG-3237180', 's'  =>'88-BELG-3206112', 'd' => '88-BELG-3206173' ),
    array('bandnumber' => '88-BELG-3206112', 's'  =>'81-BELG-3238253', 'd' => '87-BELG-3008002' ),
    array('bandnumber' => '88-BELG-3206173', 's'  =>'', 'd' => '' ),
    array('bandnumber' => '96-BELG-3156295', 's'  =>'88-BELG-3206112', 'd' => '85-BELG-3049648' ),
    array('bandnumber' => '85-BELG-3049648', 's'  =>'', 'd' => '' ),
    array('bandnumber' => '81-BELG-3238253', 's'  =>'', 'd' => '' ),
    array('bandnumber' => '87-BELG-3008002', 's'  =>'', 'd' => '' ),
);

我正在尝试以编程方式将上述数组转换为以下多维数组树:

$coiNestedArray = array('bandnumber' => '02-BELG-2129929',
               's' => array('bandnumber' => '94-BELG-3237180',
                     's' => array('bandnumber' => '88-BELG-3206112',
                           's' => array('bandnumber' => '81-BELG-3238253',
                                                 's' =>'',
                                                 'd' => ''
                           ),
                           'd' => array('bandnumber' => '87-BELG-3008002',
                                                 's' =>'',
                                                 'd' => ''
                           )
                     ),
                     'd' => array('bandnumber' => '88-BELG-3206173',
                           's' =>'',
                           'd' => ''
                     )
               ),
               'd' => array('bandnumber' => '96-BELG-3156295',
                     's' => array('bandnumber' => '88-BELG-3206112',
                           's' => array('bandnumber' => '81-BELG-3238253',
                                                 's' =>'',
                                                 'd' => ''
                           ),
                           'd' => array('bandnumber' => '87-BELG-3008002',
                                                 's' =>'',
                                                 'd' => ''
                           )
                     ),
                     'd' => array('bandnumber' => '85-BELG-3049648',
                           's' =>'',
                           'd' => ''
                     )
               )
        );

这是我到目前为止最接近的,但是它只会更新数组的第一个节点:

function findKey($coiarray, $bandnumber){
    $thisCol = array_column($coiarray, 'bandnumber');
    $found_key = array_search($bandnumber, $thisCol);
    return $found_key;
}


foreach ($coiArray as $key => $value) {

    $s = '';

    $found_key = findKey($coiArray,$coiArray[$key]['s']);
    if(isset($coiArray[$found_key])){
        $s = $coiArray[$found_key];
    }

    $d = '';

    $found_key = findKey($coiArray,$coiArray[$key]['d']);
    if(isset($coiArray[$found_key])) {
        $d = $coiArray[$found_key];
    }

    $coiArray[$key] = array('bandnumber' => $coiArray[$key]['bandnumber'], 's'  => $s, 'd' => $d );

}

我将重新排列数组的整个转储,但这是$coiArrayvar_dump($coiArray)的第一个节点,您会注意到所有最内层的嵌套[“ s“]和[” d“]键是字符串,而不是它们各自的数组。

[0]=>
  array(3) {
    ["bandnumber"]=>
    string(15) "02-BELG-2129929"
    ["s"]=>
    array(3) {
      ["bandnumber"]=>
      string(15) "94-BELG-3237180"
      ["s"]=>
      string(15) "88-BELG-3206112"
      ["d"]=>
      string(15) "88-BELG-3206173"
    }
    ["d"]=>
    array(3) {
      ["bandnumber"]=>
      string(15) "96-BELG-3156295"
      ["s"]=>
      string(15) "88-BELG-3206112"
      ["d"]=>
      string(15) "85-BELG-3049648"
    }
  }

下面的示例是$coiNestedArray中的第一个节点,我手动创建了该节点,以说明我要实现的目标。请注意,每个[“ s”]和[“ d”]都是从$coiArray派生的数组。

array(3) {
  ["bandnumber"]=>
  string(15) "02-BELG-2129929"
  ["s"]=>
  array(3) {
    ["bandnumber"]=>
    string(15) "94-BELG-3237180"
    ["s"]=>
    array(3) {
      ["bandnumber"]=>
      string(15) "88-BELG-3206112"
      ["s"]=>
      array(3) {
        ["bandnumber"]=>
        string(15) "81-BELG-3238253"
        ["s"]=>
        string(0) ""
        ["d"]=>
        string(0) ""
      }
      ["d"]=>
      array(3) {
        ["bandnumber"]=>
        string(15) "87-BELG-3008002"
        ["s"]=>
        string(0) ""
        ["d"]=>
        string(0) ""
      }
    }
    ["d"]=>
    array(3) {
      ["bandnumber"]=>
      string(15) "88-BELG-3206173"
      ["s"]=>
      string(0) ""
      ["d"]=>
      string(0) ""
    }
  }

我该如何解决这个问题?

1 个答案:

答案 0 :(得分:1)

您将需要创建一个以bandnumbers为键的关联数组,因此您可以直接通过bandnumbers查找行。然后访问这些子项,并通过引用将每个子项替换为该关联数组中的相应值。

(可选)检测哪个带号从未作为子级被引用:它是根。但是,如果您知道根带号,或者知道它始终是第一输入行中的根带号,则可以跳过最后一步。最后提取该根的值(假设正好有一个):

Select distinct  (customer_login),

           MAX(delivery_date_local) as Last_order_date,

           max(case when seqnum = 2 then

           delivery_date_local end) as Penultimate_order_date

from           (select 
^^^