Question

我正在尝试升级此博客文章中显示的示例

https://medium.com/@mitch_23203/the-exact-same-app-in-hyperstack-7f281cef46ca

使用超级堆栈模型（如后续博客文章），但这是行不通的。

更改后，这是我的代码：

class TodoIndex < HyperComponent

  def create_new_todo_item
    Todo.create(title: @todo)
    @title = nil
  end

  render(DIV, class: 'ToDo') do
    IMG(class: 'Logo', src: 'assets/logo.png', alt: 'Hyperstack Logo')
    H1(class: 'ToDo-Header') { 'Hyperstack To Do' }
    DIV(class: 'ToDo-Container') do
      DIV(class: 'ToDo-Content') do
        Todo.each do |item|
          TodoItem(key: item, item: item.title)
          .on(:delete_item) { item.destroy }
        end
      end
      DIV do
        INPUT(type: :text, value: @title)
        .on(:change) { |e| mutate @title = e.target.value }
        .on(:enter) { create_new_todo_item }
        BUTTON(class: 'ToDo-Add') { '+' }
        .on(:click) { create_new_todo_item }
      end
    end
  end
end

一切似乎都正常，并且保存了新的Todo，但属性为nil。好像标题没有保存。

Answer 1

应该是：

orders

您将SELECT tot_owed.clientname , tot_owed.Total_Owed - IIF(tot_paid.Total_Paid IS NULL, 0, tot_paid.Total_Paid) AS Balance FROM ( SELECT c.clientname , c.clientnumber , SUM(i.orderamount * i.itemprice) AS Total_Owed FROM clients c INNER JOIN orders o ON c.clientnumber = o.clientnumber INNER JOIN orderinfo i ON i.ordernum = o.ordernum GROUP BY c.clientname , c.clientnumber ) tot_owed LEFT JOIN ( SELECT c.clientname , c.clientnumber , SUM(p.payment) AS Total_Paid FROM clients c INNER JOIN payments p ON c.clientnumber = p.clientnumber GROUP BY c.clientname , c.clientnumber ) tot_paid ON tot_owed.clientnumber = tot_paid.clientnumber中的def create_new_todo_item Todo.create(title: @title) # not @todo @title = nil end设置为其状态值（title）...

不会保存记录的属性

1 个答案: