Question

我使用python中的pygame模块为基本的蛇游戏编写了代码，现在已经基本完成了，但是，我希望最后有一个游戏在屏幕上显示一些文字，重新播放并显示分数的选项。如果他们重新开始，乐谱将重置为0，然后再次播放。不幸的是，我似乎无法使该屏幕成功运行。我已经尝试了几件事，但似乎总是收到显示Surface退出的错误。如果有任何提示，我将在下面分享我的代码。

import sys, time, random, pygame
from random import randrange
pygame.init()
fps_controller = pygame.time.Clock()
#Screen Dimensions
screen_width = 600
screen_height = 600

#Screen Set Up
screen = pygame.display.set_mode((screen_width, screen_height))
pygame.display.set_caption("Snake by Bela Zumbansen")
pygame.mouse.set_visible(0)

#Colours
RED = (255, 0, 0)
GREEN = (0, 255, 0)
BLACK  = (0, 0, 0)
GREY = (200, 200, 200)
BLUE = (0, 0, 255)
WHITE = (255, 255, 255)
LIGHTBLUE = (0, 155, 155)

#Directions
RIGHT = 1
LEFT = 2
UP = 3
DOWN = 4

#Game Set Up
snake_pos = [100, 100]
snake_body = [[100, 100], [90, 100], [80, 100]]
snake_speed = 10

apple_pos = [random.randrange(1,60)*10, random.randrange(1,60)*10]
apple_spawn = True

direction = RIGHT
update = direction

scoreval = 0

def game_over():
    global run, scoreval
    screen.fill(LIGHTBLUE)
    draw_text("GAME OVER", 48, WHITE, screen_width/2, screen_height/4)
    draw_text("Score: " + str(score), 22, WHITE,  screen_width / 2, screen_height / 3)
    draw_text("Press SPACE to play again or ESC to exit", 22, WHITE, screen_width/2, screen_height / 4)
    waiting = True
    while waiting:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                pygame.quit()
            elif event.type == pygame.KEYDOWN:
                if event.key == pygame.K_SPACE:
                    scoreval = 0
                    return scoreval
                    run = True
                if event.key == pygame.K_ESCAPE:
                    pygame.quit()
            return run
def draw_text(text, size, color, x, y):
    font = pygame.font.Font('freesansbold.ttf', size)
    TextSurf, TextRect = text_objects(text, font, color)
    TextRect.center = (x, y)
    screen.blit(TextSurf, TextRect)

def text_objects(text, font, color):
    textSurface = font.render(text, True, color)
    return textSurface, textSurface.get_rect()

def eating_apple():
    global scoreval, apple_spawn
    scoreval += 1
    apple_spawn = False

def spawnApple():
    global apple_pos, apple_spawn
    apple_pos = [random.randrange(1,60)*10, random.randrange(1,60)*10]
    apple_spawn = True

def score(score):
    font = pygame.font.SysFont(None, 25)
    text = font.render("Score: "+str(score), True, WHITE)
    screen.blit(text,(10,10))

def main():
    global update, direction, run, snake_pos, snake_speed, apple_spawn, apple_pos
    pygame.time.delay(60)
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    keys = pygame.key.get_pressed()
    if keys[pygame.K_LEFT]:
        update = LEFT
    elif keys[pygame.K_RIGHT]:
        update = RIGHT
    elif keys[pygame.K_UP]:
        update = UP
    elif keys[pygame.K_DOWN]:
        update = DOWN

    if update == RIGHT and direction != LEFT:
        direction = RIGHT
    if update == LEFT and direction != RIGHT:
        direction = LEFT
    if update == UP and direction != DOWN:
        direction = UP
    if update == DOWN and direction != UP:
        direction = DOWN

    if direction == RIGHT:
        snake_pos[0] += snake_speed
    if direction == LEFT:
        snake_pos[0] -= snake_speed
    if direction == UP:
        snake_pos[1] -= snake_speed
    if direction == DOWN:
        snake_pos[1] += snake_speed

    snake_body.insert(0, list(snake_pos))
    if pygame.Rect(*snake_pos, 20, 20).colliderect(*apple_pos, 20, 20):
        eating_apple()
    else:
        snake_body.pop()
    if not apple_spawn:
        spawnApple()

    screen.fill(BLACK)
    for pos in snake_body:
        pygame.draw.rect(screen, GREEN, pygame.Rect(pos[0], pos[1], 20, 20))

    pygame.draw.rect(screen, RED, pygame.Rect(apple_pos[0], apple_pos[1], 20, 20))

    if snake_pos[0] < 0 or snake_pos[0] > screen_width-20:
        run = False
    if snake_pos[1] < 0 or snake_pos[1] > screen_height-20:
        run = False

    for block in snake_body[1:]:
        if snake_pos[0] == block[0] and snake_pos[1] == block[1]:
            run = False

    score(scoreval)
    pygame.display.update()
    fps_controller.tick(25)

#main loop
run = True
while run:
    main()


game_over()

任何提示将不胜感激

Answer 1

您需要将主循环放入另一个循环中，因此一旦完成game_over函数，它将再次开始：

# main loop
while True:
    run = True
    while run:
        main()

    game_over()

由于pygame.quit()不会退出程序，因此您需要同时使两个循环分别为while run:和两个run = True，或者使用sys.exit(0)或{{ 1}}在raise SystemExit(0)之后。

还必须在pygame.quit()函数的return run循环中删除for。

Answer 2

您有2个函数main()和game_over()，每个函数都有自己的事件循环并进行自己的绘制。
创建2个状态变量。第一个状态（run）指示游戏必须继续还是终止。
第二个状态gameover表示游戏处于“游戏结束”状态或“游戏运行”状态的天气。
根据{{1}}的状态，必须在主循环中连续调用gameover或main()。这两个函数都可以更改状态，并且必须返回状态变量的当前值。如果game_over()从gameover变为True，则必须将游戏控制变量设置为初始状态（当然，您也可以在代码中编写一个函数））：

False

游戏结束功能必须绘制“游戏结束”屏幕，当然还有run = True gameover = False while run: if not gameover: run, gameover = main() else: run, gameover = game_over() if not gameover: snake_pos = [100, 100] snake_body = [[100, 100], [90, 100], [80, 100]] snake_speed = 10 apple_pos = [random.randrange(1,60)*10, random.randrange(1,60)*10] apple_spawn = True direction = RIGHT update = direction scoreval = 0。函数评估状态变化并返回值：

pygame.display.update()

如果蛇碰撞，则def game_over(): screen.fill(LIGHTBLUE) draw_text("GAME OVER", 48, WHITE, screen_width/2, screen_height/4) draw_text("Score: " + str(score), 22, WHITE, screen_width / 2, screen_height / 3) draw_text("Press SPACE to play again or ESC to exit", 22, WHITE, screen_width/2, screen_height / 4) pygame.display.update() fps_controller.tick(25) rungame = True continuegame = False for event in pygame.event.get(): if event.type == pygame.QUIT: rungame = False elif event.type == pygame.KEYDOWN: if event.key == pygame.K_SPACE: continuegame = True if event.key == pygame.K_ESCAPE: rungame = False return rungame, not continuegame返回更改的状态：

main

使用Pygame进行Python游戏的屏幕游戏问题

2 个答案: