如何在ArrayList中选择元素的索引并更改其属性之一?

时间:2019-03-31 07:32:39

标签: java arraylist

我想更改ArrayList中某个元素的特定属性,但是我不知道如何。我想将其中一个对象的“ infected”属性更改为true。

我尝试在ArrayList上使用'set'方法将我选择的元素中的属性之一设置为其他内容,但是由于某些原因,它不起作用。

rectangles.set(5,infected=false); //I want to change the 'infected' property at element 5 to true.

public class RectangleL{
    int sX,sY;
    Color color;
    int speed;int height; int width;int velX=0;int velY=0;;
    public boolean infected=false;
//blah

4 个答案:

答案 0 :(得分:2)

get从列表中选择相关对象,然后直接对其进行操作:

rectangles.get(5).infected = true;

答案 1 :(得分:1)

只看这个:

public class Main {

    public static class RectangleL {
        int sX, sY;
        String color;
        int speed;
        int height;
        int width;
        int velX = 0;
        int velY = 0;;
        public boolean infected = false;

        public int getsX() {
            return sX;
        }

        public void setsX(int sX) {
            this.sX = sX;
        }

        public int getsY() {
            return sY;
        }

        public void setsY(int sY) {
            this.sY = sY;
        }

        public String getColor() {
            return color;
        }

        public void setColor(String color) {
            this.color = color;
        }

        public int getSpeed() {
            return speed;
        }

        public void setSpeed(int speed) {
            this.speed = speed;
        }

        public int getHeight() {
            return height;
        }

        public void setHeight(int height) {
            this.height = height;
        }

        public int getWidth() {
            return width;
        }

        public void setWidth(int width) {
            this.width = width;
        }

        public int getVelX() {
            return velX;
        }

        public void setVelX(int velX) {
            this.velX = velX;
        }

        public int getVelY() {
            return velY;
        }

        public void setVelY(int velY) {
            this.velY = velY;
        }

        public boolean isInfected() {
            return infected;
        }

        public void setInfected(boolean infected) {
            this.infected = infected;
        }

        @Override
        public String toString() {
            return "RectangleL [sX=" + sX + ", sY=" + sY + ", color=" + color + ", speed=" + speed + ", height="
                    + height + ", width=" + width + ", velX=" + velX + ", velY=" + velY + ", infected=" + infected
                    + "]";
        }

    }

    public static void main(String[] args) {
        List<RectangleL> rectangles = new ArrayList<>();
        // Let say you created a object with infected false;
        RectangleL rectangleL = new RectangleL();
        rectangleL.setColor("Red");
        rectangles.add(0, rectangleL); 
        System.out.println(rectangles.toString()); // old value
        rectangles.get(0).infected = true; // replace by new value 
        System.out.println(rectangles.toString()); // new value
    }

}

输出:

[RectangleL [sX=0, sY=0, color=Red, speed=0, height=0, width=0, velX=0, velY=0, infected=false]]
[RectangleL [sX=0, sY=0, color=Red, speed=0, height=0, width=0, velX=0, velY=0, infected=true]]

答案 2 :(得分:1)

i分析您的问题。您必须在一个变量中获取该索引的所有值,以便可以对其进行编辑。最好的方法是使用HashMap。希望下面的代码对您有所帮助。

import java.util.ArrayList;
import java.util.HashMap;

public class RectangleL {

    public static void main(String args[])
    {
        ArrayList<HashMap<String,String>> lstShap = new ArrayList<>();
        HashMap<String,String> shape1 = new HashMap<>();
        HashMap<String,String> shape2 = new HashMap<>();
        lstShap.clear();
        shape1.put("width","30");
        shape1.put("height","40");
        shape1.put("infected","false");
        lstShap.add(0,shape1);

        shape2.put("width","20");
        shape2.put("height","49");
        shape2.put("infected","false");
        lstShap.add(1,shape2);

        System.out.println(lstShap.toString());
        shape1=lstShap.get(1);
        System.out.println(shape1.toString());
        shape1.put("infected","true");
        lstShap.set(1,shape1);

        System.out.println(lstShap.toString());
    }
}

输出::

[{infected=false, width=30, height=40}, {infected=false, width=20, height=49}]
{infected=false, width=20, height=49}
[{infected=false, width=30, height=40}, {infected=true, width=20, height=49}]

答案 3 :(得分:1)

首先需要从ArrayList中获取要更改的对象。请记住,ArrayList只是对象的容器。一旦获得所需的对象,就可以像处理对象一样处理它。 因此可以是:

RectangleL rectangle = rectangles.get(5);   
rectangle.infected = true;

除此之外,还建议您在类中创建一个getter和setter方法,并将受感染的字段设为私有,以便您可以更好地控制如何访问和修改字段。

祝你好运

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