Question

在这段代码中，我有多个复选框，即name="recruiter_id"和多个提交按钮。现在，当我单击第一行提交按钮时它会发出警报数据，但是当我单击最后一行提交按钮时它会显示错误的recruiter_id，我不知道为什么吗？因此，如何获得不同的recruiter_id onclick不同的提交按钮？请帮我。

<?php
    foreach($wishlist as $row)
    {
?>
        <tr>
            <td>
                <input type="checkbox" name="recruiter_id" value="<?php echo $row['rid']; ?>" class="recruiter_id">
            </td>
            <td>
                <input type="submit" id="<?php echo $row['job_id']; ?>" class="btn btn-danger job_id" value="Assign" />
            </td>
        </tr>
<?php
    }
?>
<script>
    $(document).ready(function() {
        $(".job_id").click(function(e){
            e.preventDefault();
            job_id = this.id;
            recruiter_id = $("input[name='recruiter_id']:checked").val();
            alert(job_id);
            alert(recruiter_id);
        });
    });
</script>

Answer 1

尝试这个

<?php
foreach($wishlist as $row)
  {
?>
    <tr>
        <td>
            <input type="checkbox" name="recruiter_id" value="<?php echo $row['rid']; ?>" class="recruiter_id">
        </td>
        <td>
            <input type="submit" id="<?php echo $row['job_id']; ?>" data-val="<?php echo $row['rid']?>" class="btn btn-danger job_id" value="Assign" />
        </td>
    </tr>
 <?php
  }
 ?>
   <script>
    $(document).ready(function() {
    $(".job_id").click(function(e){
        e.preventDefault();
        job_id = this.id;
        recruiter_id = $(this).data("val");
        //$("input[name='recruiter_id']:checked").val();
        alert(job_id);
        alert(recruiter_id);
    });
});

Answer 2

您可以尝试document.getElementById（“复选框的#yourid”）。val（）它将为您提供值

Answer 3

首先，将输入类型更改为button而不是commit：

<input type="button" id="<?php echo $row['job_id']; ?>" data-val="<?php echo $row['rid']?>" class="btn btn-danger job_id" value="Assign" />

然后在点击事件内部转到父tr并检查ID，使用.closest()和:checked选中相关复选框，如：

$(document).ready(function() {
  $(".job_id").click(function(e) {
    e.preventDefault();

    var job_id = this.id;
    var recruiter_id = $(this).closest('tr').find("input[name='recruiter_id']:checked").val();

    console.log('job ID : ' + job_id + ' --- Recruiter ID:' + recruiter_id);
  });
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table border=1>
  <tr>
    <td>
      <input type="checkbox" name="recruiter_id" value="1" class="recruiter_id">1
    </td>
    <td>
      <input type="button" id="1" class="btn btn-danger job_id" value="Assign" />
    </td>
  </tr>
  <tr>
    <td>
      <input type="checkbox" name="recruiter_id" value="2" class="recruiter_id">2
    </td>
    <td>
      <input type="button" id="2" class="btn btn-danger job_id" value="Assign" />
    </td>
  </tr>
  <tr>
    <td>
      <input type="checkbox" name="recruiter_id" value="3" class="recruiter_id">3
    </td>
    <td>
      <input type="button" id="3" class="btn btn-danger job_id" value="Assign" />
    </td>
  </tr>
</table>

如何获取复选框值onclick提交按钮？

3 个答案: