Question

说我有一个由一位整数组成的数组

[1,0,2,3,6,7,9,8]

我将如何将它们转换为2位整数的数组？

像这样：

[10, 23, 67, 98]

Answer 1

您可以缩小数组并将第n ^th值用作索引。

此方法适用于每个分组数字计数。

library(stringr)
str_detect(s, "^[:upper:]+$")

const
    group = (array, digits) => array.reduce((r, v, i) => {
        var j = Math.floor(i / digits);
        r[j] = (r[j] || 0) * 10 + v;
        return r;
    }, [])

console.log(group([1, 0, 2, 3, 6, 7, 9, 8], 2));
console.log(group([1, 0, 2, 3, 6, 7, 9, 8, 9], 3));
console.log(group([1, 0, 2, 3, 6, 7, 9, 8], 4));

Answer 2

您可以使用Array.from()创建一个具有原始array.length /块大小（在您的情况下为2）的长度的新数组。用Array.slice()提取每个块，加入并转换回数字：

const chunkAndJoin = (chunkSize, arr) => 
  Array.from({ length: Math.ceil(arr.length / chunkSize) }, (_, i) => 
    Number(arr.slice(i * chunkSize, (i + 1) * chunkSize).join(''))
  )

const arr = [1,0,2,3,6,7,9,8]

const result = chunkAndJoin(2, arr)

console.log(result)

Answer 3

您可以通过使用迭代索引将Array.prototype.reduce()和concat数字用作字符串：

const initial = [1,0,2,3,6,7,9,8];
const nextArr = initial.reduce((acc, value, index) => {
  if (index % 2 !== 0) return acc;
  acc.push(Number(String(value) + String(initial[index + 1])));
  return acc;
}, []);

console.log(nextArr);

Answer 4

您可以使用.reduce()，方法是检查累积数组中的最后一项是否小于10（应追加该项），否则，可以将其添加到数组中。

请参见以下示例：

const arr = [1,0,2,3,6,7,9,8];

const res = arr.reduce((acc, n) => {
  let last = acc.length-1;
  if(acc[last] < 10) {
    acc[last] = acc[last]*10 + n;
  } else {
    acc.push(n);
  }
  return acc;
}, []);

console.log(res);

Answer 5

我不知道javascript：D，但是类似这样。

Exception in thread "main" java.lang.Error: 

    java.io.FileNotFoundException: null\lib\tzdb.dat (The system cannot find the path specified)
        at sun.util.calendar.ZoneInfoFile$1.run(ZoneInfoFile.java:261)
        at java.security.AccessController.doPrivileged(Native Method)
        at sun.util.calendar.ZoneInfoFile.<clinit>(ZoneInfoFile.java:251)
        at sun.util.calendar.ZoneInfo.getTimeZone(ZoneInfo.java:589)
        at java.util.TimeZone.getTimeZone(TimeZone.java:560)
        at java.util.TimeZone.setDefaultZone(TimeZone.java:666)
        at java.util.TimeZone.getDefaultRef(TimeZone.java:636)
        at java.util.TimeZone.getDefault(TimeZone.java:625)
        at org.sqlite.date.FormatCache.getInstance(FormatCache.java:74)
        at org.sqlite.date.FastDateFormat.getInstance(FastDateFormat.java:129)
        at org.sqlite.core.CoreConnection.<init>(CoreConnection.java:70)
        at org.sqlite.jdbc3.JDBC3Connection.<init>(JDBC3Connection.java:25)
        at org.sqlite.jdbc4.JDBC4Connection.<init>(JDBC4Connection.java:24)
        at org.sqlite.SQLiteConnection.<init>(SQLiteConnection.java:45)
        at org.sqlite.JDBC.createConnection(JDBC.java:114)
        at org.sqlite.JDBC.connect(JDBC.java:88)
        at java.sql.DriverManager.getConnection(DriverManager.java:664)
        at java.sql.DriverManager.getConnection(DriverManager.java:270)
        at repository.JdbcUtils.getNewConnection(JdbcUtils.java:39)
        at repository.JdbcUtils.getConnection(JdbcUtils.java:52)
        at repository.RepositoryLog.findOne(RepositoryLog.java:28)
        at Main.main(Main.java:28)
    Caused by: java.io.FileNotFoundException: null\lib\tzdb.dat (The system cannot find the path specified)
        at java.io.FileInputStream.open0(Native Method)
        at java.io.FileInputStream.open(FileInputStream.java:195)
        at java.io.FileInputStream.<init>(FileInputStream.java:138)
        at sun.util.calendar.ZoneInfoFile$1.run(ZoneInfoFile.java:255)
        ... 21 more

P.S。，如果您的数组长度％2！= 0，则此代码将跳过最后一个元素））

Answer 6

您可以使用法线进行循环并将i乘以2并乘以10

let array = [1, 0, 2, 3, 6, 7, 9, 8]

let finalArray = [];

for (let i = 0; i < array.length; i += 2) {
  finalArray.push(array[i]*10 + (array[i + 1]))
}
console.log(finalArray)

如何将一位整数数组转换为2位或更多位

6 个答案: